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4 years ago

If 32.3 grams of KCl are dissolved in 192 grams of water, what is the concentration of the solution in percent by mass?

Chemistry

2 answers:

vichka [17]4 years ago

6 0

Answer:

The concentration of the solution in percent by mass is 14.3%

Explanation:

Given:

Mass of KCl (solute) = 32.3 g

Mass of water (solvent) = 192 g

To determine:

Concentration of solution in % mass i,e. %(w/w)

Formula:

%w/w $= \frac{Mass\ of\ solute}{Total\ mass\ of\ solution } *100\\$

Total mass of solution = solute + solvent = 32.3 + 192 = 224.3 g

%w/w = $\frac{32}{224.3} *100 = 14.3%$

Likurg_2 [28]4 years ago

3 0

The concentration is 0.168 g/ml

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makkiz [27]

Answer:

Percent yield of SiC is 77.0%.

Explanation:

Balanced reaction: $SiO_{2}+3C\rightarrow SiC+2CO$

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So, 100.0 kg of $SiO_{2}$ = $\frac{100.0\times 10^{3}}{60.08}$ moles of $SiO_{2}$ = 1664 moles of $SiO_{2}$

According to balanced equation, 1 mol of $SiO_{2}$ produces 1 mol of SiC

Therefore, 1664 moles of $SiO_{2}$ produce 1664 moles of SiC

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4 0

3 years ago

The heat capacity of water is 1cal degree'g1 (1 calorie per degree centigrade, per gram). You are given 1 gallon of water at 25

sdas [7]

Answer:

The heat needed to boil 1 gallon of water is 81,490.62 Joules.

Explanation:

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Where:

Q = heat absorbed or heat lost

c = specific heat of substance

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ΔT = change in temperature of the substance

We have :

Volume of water = V = 1 gal = 4546.09 mL

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9 (boiling pint of water is 100°C)

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3 years ago

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Answer:

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3 years ago

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3 years ago