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Taya2010 [7]
3 years ago
7

5 1/6•(-2/5)= Answer as a fraction

Mathematics
1 answer:
lapo4ka [179]3 years ago
6 0
-31/15 is the correct answer
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if we use a number cube with the numbers 1-6 and assign 1-4 as temperature above 80 degrees F and a 5-6 as a temperature of 80 d
Andreas93 [3]

Answer:

Keep track of every 1,2,3 or 4 rolled in 30 rolls. These represent the number of days the temperatures is above 80 degrees F. Repeat this 100 times

Step-by-step explanation:


3 0
2 years ago
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C
Zolol [24]

The  value of this expression when =-2 and x=-1 is: 3.

<h3>Value of the expression</h3>

Given equation:

-2 and x=-1

Solving the value of the given equation

-2 and x=-1

Hence:

=-(-1)+2

=1+2

=3

Therefore the value of this expression when =-2 and x=-1 is: 3.

Learn more about Value of the expression here:

brainly.com/question/912391

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2 years ago
the school for unfair I made 1768 on games and 978 on food sales how much money did the fun fair make on games and food sales
Svetlanka [38]
2746.
Cheater from Go Math.
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6 0
3 years ago
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Question 11 (5 points)
Semenov [28]

Hello :)

here you need to use the slope intercept formula to find your equation:

y= mx+b

b= the y- intercept

m= the slope

we are already given the slope and the x & y

y=-3x+(-2)

your answer would be a) y = -3x - 2

8 0
3 years ago
An ice chest contains cans of apple juice, cans of grape juice, cans of orange juice, and cans of mango juice. Suppose that you
mel-nik [20]

Answer:

4.9%

Step-by-step explanation:

This question is incomplete. However; it can be found on search engines. The complete question is  as follows :

An ice chest contains cans of six apple juice, eight cans of grape juice, four cans of orange juice, and two cans of mango juice. Suppose that you reach into the container and randomly select three cans in succession. Find the probability of selecting three cans of grape juice.

Solution :

In an ice chest there are different cans of juice. Among them

Number of cans of apple juice = 6

Number of cans of grape juice = 8

Number of cans of orange juice = 4

Number of cans of mango juice = 2

Total number of cans of juice = 6 + 8 + 4 + 2 = 20

Let A, B and C are the event of selecting of three cans.  The events A, B and C are dependent.

Probability of selecting three cans of juice

P = \frac{\text{number of grape cans}}{\text {total number of cans}}

P (A) = \frac{8}{20}

P (B) = \frac{7}{19}

P (B) = \frac{6}{18}

P = \frac{8}{20} × \frac{7}{19} × \frac{6}{18}

  = \frac{336}{6840}

  = 0.049 or 4.9%

Probability of selecting three cans of grape juice is 4.9%

5 0
3 years ago
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