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Gnom [1K]
3 years ago
8

Are the base pairs always the same?

Chemistry
2 answers:
Ivanshal [37]3 years ago
7 0

The nucleotides<span> in a </span>base pair<span> are complementary which means their shape allows them to bond together with hydrogen bonds. The A-T </span>pair<span> forms two hydrogen bonds. The C-G </span>pair<span> forms three. The hydrogen bonding between complementary</span>bases<span> holds the two strands of DNA together.</span>

Monica [59]3 years ago
6 0
No  because they can be seperated differently

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How many potassium atoms are in 250.0 grams of potassium?
loris [4]

Hi!


The correct option would be 3.85x10^(24)


To find the number of atoms in 250g of potassium, we need to first calculate the number of atoms in


1 mole of Potassium = 39g which contains 6.022x10^(23) atoms of K

<em>(Avogadro's constant value for the amount of molecules/atoms in one mole of any substance)</em>

<em>Solution</em>

So as 39g of Potassium contains 6.022x10^(23) K atoms

1g of Potassium would contain 6.022x10^(23) / 39 = 1.544 x10^(22) atoms

So 250g of Potassium would contain 1.544x10^(22) x 250 = 3.86x10^(24) atoms

3 0
3 years ago
The concentration of species in 500 mL of a 2.104 M solution of sodium sulfate is ________ M sodium ion and ________ M sulfate i
omeli [17]

Answer:

The concentration of species in 500 mL of a 2.104 M solution of sodium sulfate is 4.208 M sodium ion and 2.104 M sulfate ion.  (option E)

Explanation:

Step 1: Data given

Volume = 500 mL = 0.500 L

The concentration sodium sulfate = 2.104 M

Step 2: The equation

Na2SO4 → 2Na+ + SO4^2-

For 1 mol Na2SO4 we have 2 moles sodium ion (Na+) and 1 mol sulfate ion (SO4^2-)

Step 3: Calculate the concentration of the ions

[Na+] = 2*2.104 M = 4.208 M

[SO4^2-] = 1*2.104 M = 2.104 M

The concentration of species in 500 mL of a 2.104 M solution of sodium sulfate is 4.208 M sodium ion and 2.104 M sulfate ion.  (option E)

8 0
2 years ago
X-x/4-1/3=2+x/4 please answer me ​
Karo-lina-s [1.5K]

Answer:

x= 14/3 = 4.667

Explanation:

X - X/4 - 1/3 = 2 + X/4

7 0
3 years ago
Calculate the Molarity (M) of an aqueous solution of HCl which is 35.38% HCl by mass and has a density of 1.161 g/mL.
kozerog [31]

Answer:

11.2 M → [HCl]

Explanation:

Solution density = Solution mass / Solution volume

35.38 % by mass, is the same to say 35.38 g of solute in 100 g of solution.

Let's determine the moles of our solute, HCl

35.38 g . 1 mol/36.45 g = 0.970 moles

Let's replace the data in solution density formula

1.161 g/mL = 100 g / Solution volume

Solution volume = 100 g / 1.161 g/mL → 86.1 mL

Let's convert the volume to L → 86.1 mL . 1L / 1000 mL = 0.0861 L

Molarity (M) → mol/L = 0.970 mol / 0.0861 L → 11.2 M

8 0
3 years ago
Select the correct answer.
vaieri [72.5K]

Answer:

b

Explanation:

compounds ..........

6 0
2 years ago
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