Are the base pairs always the same?
2 answers:
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Answer: The empirical formula is and molecular formula is
Explanation:
We are given:
Mass of = 18.95 g
Mass of = 7.759 g
Molar mass of carbon dioxide = 44 g/mol
Molar mass of water = 18 g/mol
For calculating the mass of carbon:
In 44g of carbon dioxide, 12 g of carbon is contained.
So, in 18.59 g of carbon dioxide, = of carbon will be contained.
For calculating the mass of hydrogen:
In 18g of water, 2 g of hydrogen is contained.
So, in 7.759 g of water, = of hydrogen will be contained.
Mass of C = 5.07 g
Mass of H = 0.862 g
Step 1 : convert given masses into moles.
Moles of C =
Moles of H=
Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.
For C =
For H =
The ratio of C : H = 1: 2
Hence the empirical formula is .
The empirical weight of = 1(12)+2(1)= 14 g.
The molecular weight = 56.1 g/mole
Now we have to calculate the molecular formula.
The molecular formula will be=
Answer:
Answer: (1R,2S) / (1S, 2R) , (1R,2R) / (1S, 2S)
Explanation:
Sodium borohydride reduction of benzoin will give four possible stereo isomers out of which are (1R,2S) - (1S, 2R) isomers and (1R,2R) - (1S, 2S) isomers which are known as enantiomers.
In general enantiomers show single spot in the TLC as they do not show any difference in Rf value (i.e) (1R,2S) - (1S, 2R) isomers show only one spot although they are two compounds and also (1R,2R) - (1S, 2S) isomers also show one spot. That is the reason why you are observing two spots in the TLC ( of reaction mixture) other than starting materilal.
