<span>Temperature is defined as the rate at which molecules move or vibrate
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It’s lower, hope this helps with your issue and helps solve your problem, no problem
Answer:
Mass of water = 73.08 g
Explanation:
Given data:
Mass of hydrogen = 35 g
Mass of oxygen = 65 g
Mass of water = ?
Solution:
First of all we will write the balanced chemical equation:
2H₂ + O₂ → 2H₂O
Number of moles of hydrogen = mass/ molar mass
Number of moles of hydrogen = 35 g/ 2 g/mol
Number of moles of hydrogen = 17.5 mol
Number of moles of oxygen = 65 g / 32 g/mol
Number of moles of oxygen = 2.03 moles
Now we compare the moles of water with moles hydrogen and oxygen.
H₂ : H₂O
2 : 2
17.5 : 17.5
O₂ : H₂O
1 : 2
2.03 : 2× 2.03 =4.06 mol
Number of moles of water produced by oxygen are less so oxygen is limitting reactant.
Mass of water:
Mass of water = number of moles × molar mass
Mass of water = 4.06 mol × 18 g/mol
Mass of water = 73.08 g
Answer:
The answer to your question is:
Explanation:
e) 9.10 x 10³ + 2.2 x 10⁶ = 2.2091 x 10⁶
f) 1113.0 - 14.6 x 10² = -347 = -3.47 x 10²
g) 6.18 x 10⁻⁴⁵ + 4.72 x 10⁻⁴⁴ = 5.338 x 10⁻⁴⁴
h) 4.25 x 10⁻³ - 1.6 x 10⁻² = -0.01175 = -1.175 x 10 ⁻²
5.- Calculate ...
a) 2.63 x 10⁻⁴
b) 2.26 x 10¹³
c) 1.97 x 10²
d) 1.65 x 10⁻²³
e) 2.5 x 10⁻⁸³
f) 1.61 x 10¹⁴
g) 2 x 10⁷⁹
h) 2.37 x 10⁻⁷
Answer:
d- 7.58 L
Explanation:
According to Charles's law, the temperature in Kelvin is proportional to the volume of a dry gas when the pressure is constant.
Mathematically, V1/T1 = V2/ T2
V1= initial volume= 6.6 L
T1= Initial temperature= 115 °C= (115 °C +273)=388K
V2= final volume
T2= final temperature= 173 °C= ( 173 °C+ 273)= 446K
Substitute the values,
V2=( V1 × T2)/ T1
= (6.6×446)/388
= 2943.6/388
= 7.6L
