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2 years ago

13. Base your answer to the following question on the information below and on your knowledge of chemistry.

1 answer:

8 0

From our knowledge of periodic trends, the screening effect of the inner electrons outweigh the increase in nuclear charge causing the atomic radius to increase.

<h3>Periodic trends</h3>

The periodic trends are those properties that increase or decrease down the group or across the period. These periodic trends include;

Ionization energy
Electron affinity
Atomic radius
Ionic radius etc

As more shell are added down the group in group 14, the screening effect of the inner electrons outweigh the increase in nuclear charge causing the atomic radius to increase.

Learn more about periodic trends: brainly.com/question/12074167

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Is air a conductor or insulator

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Insulator! I hope this helps! Pls mark mine the brainliest;)

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3 years ago

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What is the correct reaction for the dissociation (ionization) for a weak acid?

slava [35]

Answer: HA + H2O ⇌ H3O+ + H- (option #4)

Explanation: Since the acid is weak you have to use a ⇌ (equilibrium) sign. Equilibrium is denoted in a chemical equation by the ⇌ symbol. Also, when any acid dissolves into water, it produces hydronium (H3O+ or H+). Therefore, the fourth chemical reaction is your answer.

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2 years ago

Good evening! Does anyone know this? Earth Science

riadik2000 [5.3K]

The fraction of Earth's radius (6371 km) relative to the thickness of the oceanic (7.5 km) and continental crust (35 km) is 0.12 and 0.55, respectively.

What we know:

The average radius of Earth (E) = 6371 km

The average thickness of oceanic crust (O) = 7.5 km

The average thickness of continental crust (C) = 35 km

We need to convert all the above units from kilometers to miles:

$E = \frac{0.6214 mi}{1 km}*6371 km = 3958.9 mi$

$O = \frac{0.6214 mi}{1 km}*7.5 km = 4.7 mi$

$C = \frac{0.6214 mi}{1 km}*35 km = 21.7 mi$

Now, we can calculate the fraction of Earth's radius relative to each type of crust, with the given equation:

$X = \frac{avg. \: thickness}{avg. \: radius} \times 100$

<u>For the oceanic crust (O)</u>:

$X = \frac{4.7 mi}{3958.9 mi}\times 100 = 0.12$

<u>For the continental crust (C)</u>:

$X = \frac{21.7 mi}{3958.9 mi}\times 100 = 0.55$

Therefore, the fraction of Earth's radius relative to the oceanic and continental crust is 0.12 and 0.55, respectively.

You can see another example of calculation of fractions of Earth's radius here: brainly.com/question/4675868?referrer=searchResults

I hope it helps you!

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2 years ago

A solution is made by dissolving 15.5 grams of glucose (C6H12O6) in 245 grams of water. What is the freezing point depression of

sergij07 [2.7K]

From the equation; ΔTf = Kf × m
Where, Kf for water = 1.853 K kg/mole; m is the molarity = number of solute/amount of solvent in kg.
Glucose is the solute whose molecular mass is 180 g/mole and water is the solvent.
Moles of solute = 15.5/180 = 0.0861 moles
Amount of solvent in kg = 245/1000 = 0.245 Kg
Therefore; molarity = 0.0861/0.245 = 0.3515 moles/Kg
Therefore; ΔTf = 1.853 × 0.3515 = 0.6513 K
Hence; the depression in freezing point is 0.6513
The freezing point of solution will therefore be;
= 273 - 0.6513 = 272.3487 K

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3 years ago

I need help answering this question

Gemiola [76]

Answer:

b,d

Explanation:

An ion is an atom with a difference in the amount of protons and elektrons.

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2 years ago

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