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mezya [45]
3 years ago
9

Which of the following is NOT a model of the solar system?

Physics
2 answers:
STALIN [3.7K]3 years ago
7 0

Answer:

The correct answer is option b, Earth centered

Explanation:

For the very first it was proposed by Copernicus that it is not the earth but sun which lies at the center of the system and rest all planets revolve around the sun. This sun centered model is known as heliocentric system and is also referred to as the modern view. This model was also helpful in solving two major queries instantly –  

a) Varying brightness of planets

b) Retrograde motion.

bezimeni [28]3 years ago
3 0

Correct answer choice:

B. Earth-centered

Explanation:

Heliocentric theory is the planetary model in which the Earth and planets rotate around the Sun at the focus of the Solar System. Historically, Heliocentric theory was objected to geocentric theory, which set the Earth at the core. This approach was explained in sections by several cosmologists over various times, particularly Aristarchus, Copernicus, Kepler, and Galileo.

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Maksim231197 [3]

Answer:

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3 years ago
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What is the thinnest soap film (excluding the case of zero thickness) that appears black when illuminated with light with a wave
Firlakuza [10]

Answer:

thinnest soap film is  206.76 nm

Explanation:

Given data

wavelength = 550 nm

index of refraction n  = 1.33

to find out

What is the thinnest soap film

solution

we have wavelength  λ = 550 nm

that is  λ = 550 × 10^{-9} m

and n = 1.3

we will find the thickness of soap film as given by formula that is

thickness = λ/2n

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7 0
3 years ago
The electric field in a region of space increases from 0 to 2150 N/C in 5.00 s. What is the magnitude of the induced magnetic fi
Feliz [49]

To solve this problem we will use the Ampere-Maxwell law, which   describes the magnetic fields that result from a transmitter wire or loop in electromagnetic surveys. According to Ampere-Maxwell law:

\oint \vec{B}\vec{dl} = \mu_0 \epsilon_0 \frac{d\Phi_E}{dt}

Where,

B= Magnetic Field

l = length

\mu_0 = Vacuum permeability

\epsilon_0 = Vacuum permittivity

Since the change in length (dl) by which the magnetic field moves is equivalent to the perimeter of the circumference and that the electric flow is the rate of change of the electric field by the area, we have to

B(2\pi r) = \mu_0 \epsilon_0 \frac{d(EA)}{dt}

Recall that the speed of light is equivalent to

c^2 = \frac{1}{\mu_0 \epsilon_0}

Then replacing,

B(2\pi r) = \frac{1}{C^2} (\pi r^2) \frac{d(E)}{dt}

B = \frac{r}{2C^2} \frac{dE}{dt}

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dE = 2150N/C

dt = 5s

C = 3*10^8m/s

D = 0.440m \rightarrow r = 0.220m

Replacing we have,

B = \frac{r}{2C^2} \frac{dE}{dt}

B = \frac{0.220}{2(3*10^8)^2} \frac{2150}{5}

B =5.25*10^{-16}T

Therefore the magnetic field around this circular area is B =5.25*10^{-16}T

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