Answer:
Explanation:
Given that, the pilot can withstand 9g acceleration which is approximately 88m/s².
Now, the pilot is traveling in a circle of radius
r = 3340 m
And the speed is
v = 495 m/s
Then, acceleration?
The acceleration of a circular motion can be determine using centripetal acceleration
a = v² / r
a = 495² / 3340
a = 73.36 m/s².
Since the acceleration is less that the acceleration the pilot can withstand, then, I think the pilot makes the turn without blacking out and successfully
Answer:
The required pressure is 6.4866 atm.
Explanation:
The given data : -
In the afternoon.
Initial pressure of tire ( p₁ ) = 7 atm = 7 * 101.325 Kpa = 709.275 Kpa
Initial temperature ( T₁ ) = 27°C = (27 + 273) K = 300 K
In the morning .
Final temperature ( T₂ ) = 5°C = ( 5 + 273 ) K = 278 K
Given that volume remains constant.
To find final pressure ( p₂ ).
Applying the ideal gas equation.
p * v = m * R * T


= 657.2615 Kpa = 6.486 atm
Answer:
20 m/ s
Explanation:
change in velocity = 4m/ s


initial velocity = 0m/ s
- let velocity after 10s be v

cross multiplying

so the velocity after 10s will be 20m/s
Answer:
Option C
Explanation:
Building Restoration, Inc. (BRI) entered into a contact to refurbish an old train depot for Casual Dining which means it will renovate or redecorate the old train depot for casual dining
In case of refurbishing it will just renovate the old building and will not demolish that building
∴ If BRI completes most of the work promised in the contract, its performance will be reformation
Answer:
B . a heat transfer caused