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algol13
3 years ago
8

What is the area of a rectangle whose sides are 3.2 m and 8.01 m? Answer in units of m²

Physics
2 answers:
alexgriva [62]3 years ago
4 0

Answer:

25.632 m²

Explanation:

area = a*b

area = 3.2m * 8.01m

area = 25.632 m²

GuDViN [60]3 years ago
3 0

Explanation:

<h3>sides:3.2m,8.01m</h3><h3>area of rectangle=l×b</h3><h3>=3.2×8.01</h3>

3.2 \times 8.01 = 25.632

<h3>area=25.632m²</h3>
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When a ray of light passes through a glass slab of a certain thickness, the ray gets displaced or shifted from the original path. This is called lateral shift/displacement.

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3 years ago
A 25.0-kg test rocket is fired vertically. When the engine stops firing, the rocket’s kinetic energy is 2017 J. After the fuel i
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1. 2.12105 J. The final kinetic energy is. KE f mv2. (875.0 kg)(44.0 m/s)2 2.What is the velocity of the two hockey players after the collision? ... A 10.0-kg test rocket is fired vertically from.

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3 years ago
The mass of a particular eagle is twice that of a hunted pigeon. Suppose the pigeon is flying north at ????????,2=17.9vi,2=17.9
AleksAgata [21]

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V=27.24 m/s

Explanation:

We need to apply the linear momentum conservation theorem:

m_1*v_{o1}+m_2*v_{o2}=m_t*v_{f}\\

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2*(16.9m/s(i)+31.66m/s(j))+17.9m/s(i)=3*v_f\\v_f=17.23m/s(i)+21.10m/s(j)

because speed is a scalar value:

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4 years ago
Which best describes the electric field created by a positive charge?
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8 0
3 years ago
Yvette hangs a 2.4kg bird feeder in the middle of a rope tied between two trees, the feeder creates a
kicyunya [14]

Answer:

a) 0.049 m

b) Yes, increase

Explanation:

Draw a free body diagram.

In the y direction, there are three forces acting on the feeder.  Two vertical components of the tension forces in each rope pulling up, and weight force pulling down.

Apply Newton's second law to the feeder in the y direction.

∑F = ma

2Ty − mg = 0

Ty = mg/2

Let's say the distance the rope sags is d.  The trees are 4m apart, so the feeder is 2m horizontally from either tree.  Using Pythagorean theorem, we can find the length of the rope on either side:

L² = 2² + d²

L = √(4 + d²)

Using similar triangles, we can write a proportion using the forces and distances.

Ty / T = d / L

Substitute:

(mg/2) / T = d / √(4 + d²)

Solve for d:

Td = mg/2 √(4 + d²)

T² d² = (mg/2)² (4 + d²)

T² d² = (mg)² + (mg/2)² d²

(T² − (mg/2)²) d² = (mg)²

d² = (mg)² / (T² − (mg/2)²)

d = mg / √(T² − (mg/2)²)

Given m = 2.4 kg and T = 480 N:

d = (2.4) (9.8) / √(480² − (2.4×9.8/2)²)

d = 0.049 m

b) If a bird lands on a feeder, this will increase the tension in the rope to support the bird's weight.

8 0
3 years ago
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