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2 years ago

What is the area of a rectangle whose sides are 3.2 m and 8.01 m? Answer in units of m²

Physics

2 answers:

alexgriva [62]2 years ago

4 0

Answer:

25.632 m²

Explanation:

area = a*b

area = 3.2m * 8.01m

area = 25.632 m²

GuDViN [60]2 years ago

3 0

Explanation:

<h3>sides:3.2m,8.01m</h3><h3>area of rectangle=l×b</h3><h3>=3.2×8.01</h3>

$3.2 \times 8.01 = 25.632$

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A 20,000 kg truck is traveling at 10 m/s. Calculate the truck's momentum. (p = m v)

kow [346]

Answer:

200,000 and 20,000,000

Explanation:

Substituting the values into the equation of momentum, we get that the momentum is p = mv = 20,000*10 = 200,000. Using the equation provided to solve for the force the truck experienced, we find: 20,000*10/0.01 = 20,000,000.

I hope this helps!

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3 years ago

What is the unit of k (spring constant) in SI system?

Gre4nikov [31]

Answer:

SI unit of k (spring constant) = N/m

Explanation:

We have expression for force in a spring extended by x m given by

F = kx

Where k is the spring constant value.

Taking units on both sides

Unit of F = Unit of k x Unit of x

N = Unit of k x m

Unit of k = N/m

SI unit of k (spring constant) = N/m

7 0

3 years ago

Read 2 more answers

Kalea throws a baseball directly upward at time t = 0 at an initial speed of 13.7 m/s. How high h does the ball rise above its r

Trava [24]

Answer:

h = 9.57 seconds

Explanation:

It is given that,

Initial speed of Kalea, u = 13.7 m/s

At maximum height, v = 0

Let t is the time taken by the ball to reach its maximum point. It cane be calculated as :

$v=u-gt$

$u=gt$

$t=\dfrac{u}{g}$

$t=\dfrac{13.7}{9.8}$

t = 1.39 s

Let h is the height reached by the ball above its release point. It can be calculated using second equation of motion as :

$h=ut+\dfrac{1}{2}at^2$

Here, a = -g

$h=ut-\dfrac{1}{2}gt^2$

$h=13.7\times 1.39-\dfrac{1}{2}\times 9.8\times (1.39)^2$

h = 9.57 meters

So, the height attained by the ball above its release point is 9.57 meters. Hence, this is the required solution.

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3 years ago

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alina1380 [7]

Answer:

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Explanation:

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2 years ago

After a check up, a person now has a far point of 100 cm, but with good near point vision. He needs to wear a new pair of correc

lakkis [162]

Answer:

so his far point according to this pair of glass is 200 cm

Explanation:

power of old pair of corrective glasses is given as

$P = -0.5 dioptre$

now we have

$f = \frac{1}{P}$

$f = -2 m$

$f = -200 cm$

now we know that for normal vision the maximum distance of vision is for infinite distance

so by lens formula we have

$\frac{1}{d_i} + \frac{1}{d_o} = \frac{1}{f}$

$\frac{1}{d_i} + 0 = \frac{1}{200}$

$d_i = 200 cm$

so his far point according to this pair of glass is 200 cm

7 0

3 years ago