The given compound is being synthesized by condensing
Acetone and
Pivaldehyde (Trimethylacetaldehyde).
First Acetone is treated with
Base, the base abstracts the mildly acidic proton present at alpha position to carbonyl group. The resulting specie called
enolate act as a nucleophile and attacks on highly reactive aldehyde which upon
dehydration yields the
Aldol Product. The Reaction is as follow,
Answer:
= 97.44 Liters at S.T.P
Explanation:
The reaction between Iron (iii) oxide and Carbon monoxide is given by the equation;
Fe2O3(s)+ 3CO(g) → 3CO2(g) + 2Fe(s)
From the reaction when the reactants react, 2 moles of Fe and 3 moles of CO2 are produced.
Therefore; Mole ratio of Iron : Carbon dioxide is 2:3
Thus; Moles of Carbon dioxide = (2.9/2)×3
= 4.35 moles
But; 1 mole of CO2 at s.t.p occupies 22.4 liters
Therefore;
Mass of CO2 = 22.4 × 4.35 Moles
= 97.44 L
Explanation:
(a) As the given chemical reaction equation is as follows.

So, when we double the amount of hypochlorite or iodine then the rate of the reaction will also get double. And, this reaction is "first order" with respect to hypochlorite and iodine.
Hence, equation for rate law of reaction will be as follows.
Rate =
(b) Since, the rate equation is as follows.
Rate =
Let us assume that (
)
Putting the given values into the above equation as follows.

K =
=
Hence, the value of rate constant for the given reaction is
.
(c) Now, we will calculate the rate as follows.
Rate =
=
= 
Therefore, rate when
M and
M is
.