Answer is: <span>the half-life of the radioisotope is 74 days.
</span>m₀ = 3.25 g.
m₁ = 1.21 g.
t = 105 d.
ln(m₀/m₁) = k· t.
ln(3.25/1.21) = k·105 d.
ln(2.685) = 105·k.
0.98 = 105k.
k = 0.0094.
t1/2 = ln2 / k.
t1/2 = 0.693 / 0.0094.
t1/2 = 73.72 days.
Answer:
9.57 mol.
Explanation:
<em>Molarity is defined as the no. of moles of a solute per 1.0 L of the solution.</em>
<em />
<em>M = (no. of moles of solute)/(V of the solution (L)).</em>
<em></em>
∴ M = (no. of moles of sucrose)/(V of the solution (L)).
1.1 M = (no. of moles of sucrose)/(8.7 L).
<em>∴ no. of moles of sucrose = (1.1 M)(8.7 L) = 9.57 mol.</em>
First, let's state the chemical reaction:
We can find the number of moles of Cl2 required to produce 0.0923 moles of AlCl3, doing a rule of three: 3 moles of Cl2 reacted produces 2 moles of AlCl3:
The calculation would be:
And the final step is to convert this number of moles to grams. Remember that the molar mass can be calculated using the periodic table, so the molar mass of Cl2 is 70.8 g/mol, and the conversion is:
The answer is that we need 9.770 grams of Cl2 to produce 0.0923 moles of AlCl3.
I think it’s A but, don’t come at me if I’m wrong. Btw I read over it multiple times so this isn’t a random guess. Good luck tell me if you got it right
