Answer:
The correct option is methane :
.
Explanation:
Average speed of the gas molecules id given by expression:

k = Boltzmann cosnatnt
T = Temperature of the gas molecules = 355 K
m = molecular mass of the molecule

Molar mass of methane = 18 g/mol
Molar mass of neon = 20.18 g/mol
Molar mass of ethene = 28 g/mol
Molar mass of chlorine gas = 70 g/mol
Lower the value of molar mass of gas molecule higher will be the average speed.So, from the given options methane gas greatest average seed because it has lowest molecular mass
Answer:
Percent yield = 69.4%
Explanation:
Given data:
Percent yield = ?
Actual yield of copper = 4.65 g
Mass of aluminium = 1.87 g
Mass of copper sulfate = excess
Solution:
Chemical equation:
2Al + 3CuSO₄ → Al₂(SO₄)₃ + 3Cu
Number of moles of Aluminium:
Number of moles = mass/ molar mass
Number of moles = 1.87 g/27 g/mol
Number of moles = 0.07 mol
Now we will compare the moles of Al with copper.
Al : Cu
2 : 3
0.07 : 3/2×0.07 =0.105 mol
Mass of Copper:(Theoretical yield)
Mass = Number of moles × molar mass
Mass = 0.105 mol × 63.5 g/mol
Mass = 6.7 g
Percent yield:
Percent yield = Actual yield / theoretical yield × 100
Percent yield = 4.65 g/ 6.7 g × 100
Percent yield = 69.4%
Answer:
glucose
Explanation:
There are two types of respiration:
1. Aerobic respiration
2. Anaerobic respiration
Aerobic respiration:
It is the breakdown of glucose molecule in the presence of oxygen to yield large amount of energy. Water and carbon dioxide are also produced as a byproduct.
Glucose + oxygen → carbon dioxide + water + 38ATP
Anaerobic Respiration:
It is the breakdown of glucose molecule in the absence of oxygen and produce small amount of energy. Alcohol or lactic acid and carbon dioxide are also produced as byproducts.
Glucose→ lactic acid/alcohol + 2ATP + carbon dioxide
This process use respiratory electron transport chain as electron acceptor instead of oxygen. It is mostly occur in prokaryotes. Its main advantage is that it produce energy (ATP) very quickly as compared to aerobic respiration.
Steps involve in anaerobic respiration are:
Glycolysis:
Glycolysis is the first step of both aerobic and anaerobic respiration. It involve the breakdown of one glucose molecule into pyruvate and 2ATP.
Fermentation:
The second step of anaerobic respiration is fermentation. It involve the fermentation of pyruvate into lactic acid or alcohol depending upon the organism in which it is taking place. There is no ATP produced in this step, however carbon dioxide is released.
Answer:
It would move either left or right
Explanation: Taking assumption that,
Fructose + ATP fructose - 6 - phosphate + ADP (The standard free energy of hydrolysis for fructose-6-phosphate is - 15.9 kJ/mol.) 3 - phosphoglycerate + ATP 1,3 - bisphosphoglycerate + ADP (The standard free energy of hydrolysis for 1,3-bisphosphoglycerate is - 4 9.3 kJ/mol.) pyruvate + ATP phosphoenolpyruvate + ADP (The standard free energy of hydrolysis for phosphoenolpyruvate -is -61.9 kJ/mol.)