Answer:
123.0*12.35/(0.05*6.049)
first do in small bracket 123.0*12.35/0.30245
and then divide 123.0*40.83319557
and multiply 5022.483055
MnCl2(aq) is an ionic compound which will have the releasing of 2 Cl⁻ ions ions in water for every molecule of MnCl2 that dissolves.
MnCl2(s) --> Mn+(aq) + 2 Cl⁻(aq)
[Cl⁻] = 0.92 mol MnCl2/1L × 2 mol Cl⁻ / 1 mol MnCl2 = 1.8 M
The answer to this question is [Cl⁻] = 1.8 M
It is better for the whales to go where the whales have the ability to dive longer and deeper to find cooler water.
Explanation:
Sodium has atomic number of 11 and its electronic configuration is given by:
![[Na]=1s^22s^22p^63s^1](https://tex.z-dn.net/?f=%5BNa%5D%3D1s%5E22s%5E22p%5E63s%5E1)
The nearest stable electronic configuration to sodium is of the neon. So, in order to attain stability of noble gas it will loose its single electron.
![[Na^+]=1s^22s^22p^63s^0](https://tex.z-dn.net/?f=%5BNa%5E%2B%5D%3D1s%5E22s%5E22p%5E63s%5E0)
Sodium has single valency that is 1.
Let nbe the valency of the ion 'X'
By criss-cross method, the oxidation state of the ions gets exchanged and they form the subscripts of the other ions. This results in the formation of a neutral compound.
So, the formulas for all the possible compounds that sodium can form with the other ions will be:
Hey there!:
The balanced reaction is as follows
NiCO3(s) + 2HI(aq) ⇌ NiI2(aq) + CO2(g) + H2O(l)
The net ionic equation shows all the ions that react or change state. In this case, the only ion that does not change state is the I⁻ ion (in both reactant and product, it is aqueous).
Therefore the net ionic equation is:
NiCO3(s) + 2H⁺(aq) ⇌ Ni²⁺(aq) + CO2(g) + H2O(l)
Hope that helps!
