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OLEGan [10]
3 years ago
5

What does the number 5 represent in 5 AlPO4

Chemistry
1 answer:
olga2289 [7]3 years ago
4 0

Answer: The number 5 represents the coefficient, which is also equal to the number of moles of the formula unit above.

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Which of the following pairs of elements are likely to form ionic compounds? Check all that apply. Check all that apply. magnesi
Roman55 [17]

Answer:

magnesium and chlorine

Explanation:

An ionic bond is usually formed between a metal and a nonmetal. An ionic bond involves the transfer of one or more electrons from a highly electro positive metal to a nonmeta.

Usually, the electro negativity difference between the two species involved in an ionic bond is usually high.

For instance, the electro negativity of magnesium is 1.31 while that of chlorine is 3.16. This implies that they have a difference in electro negativity of about 1.85 between them which is large enough to be considered as leading to a pure ionic bond. An electro negativity difference above 1.7 is generally regarded as leading to the formation of an ionic bond.

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I think it is b that is what my teacher said

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Im pretty sure it's D.
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How many atoms of each type of element does this represent ?
lorasvet [3.4K]
5Al2(SO4)3

5 molecules of aluminum sulfate

5(2Al 3S 4·3O)
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3 years ago
A 3.00g of a certain Compound X, known to be made of carbon, hydrogen and perhaps oxygen, and to have a molecular molar mass of
andrew-mc [135]

Answer: The molecular formula for the given organic compound X is C_6H_{8}O_7

Explanation:

We are given:

Mass of CO_2=4.13g

Mass of H_2O=1.13g

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44g of carbon dioxide, 12 g of carbon is contained.

So, in 4.13 g of carbon dioxide, =\frac{12}{44}\times 4.13=1.13g of carbon will be contained.

For calculating the mass of hydrogen:

In 18g of water, 2 g of hydrogen is contained.

So, in 1.13 g of water, \frac{2}{18}\times 1.13=0.125g of hydrogen will be contained.

Mass of oxygen in the compound = (3.00) - (1.13+ 0.125) = 1.75 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon =\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{1.13g}{12g/mole}=0.094moles

Moles of Hydrogen =\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.125g}{1g/mole}=0.125moles

Moles of Oxygen =\frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{1.75g}{16g/mole}=0.109moles

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles

For Carbon = \frac{0.094}{0.094}=1

For Hydrogen = \frac{0.125}{0.094}=1.33

For Oxygen = \frac{0.109}{0.094}=1.16

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : O = 1: 1.33: 1.16

Converting them into whole number ratios by multiplying by 6:

The ratio of C : H : O = 6: 8: 7

Hence, the empirical formula for the given compound is C_6H_8O_7

Empirical mass = 6\times 12+8\times 1+7\times 16=192g

The equation used to calculate the valency is :

n=\frac{\text{molecular mass}}{\text{empirical mass}}

Putting values in above equation, we get:

n=\frac{192g/mol}{192g/mol}=1

Multiplying this valency by the subscript of every element of empirical formula, we get:

C_6H_8O_7\times 1=C_6H_{8}O_7

Thus molecular formula for the given organic compound X is C_6H_{8}O_7

7 0
3 years ago
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