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andreev551 [17]
2 years ago
9

Hey please help Hey please help Hey please help Hey please help Hey please help

Physics
1 answer:
meriva2 years ago
6 0
No they aren't the same
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A 90kg person jumps from a 30m tower into a tub of water with a volume of 5m3 initially at 20°C. Assuming that all of the work d
Kryger [21]

Answer:

T₂ = 20.06 ° C

Explanation:

Given

P = 90 kg,  T₁ = 20 ° C,  h = 30 m,  c = 1.82 kJ / Kg * ° C

Using the formula to determine the final temperature of the water

T₂ = T₁ * P * h / Eₐ * c

The work done of the person to the water

Eₐ = 1000 kg / m³ * 5 m³ * 9.8 m / s²

Eₐ = 49000 N

T₂ = 20 ° C +[ (90 kg * 30m) / (49000 N * 1.82) ]

T₂ = 20.06 ° C

4 0
3 years ago
A student places an object with a mass of m on a disk at a position r from the center of the disk. The student starts rotating t
koban [17]

Answer:

The coefficient of static friction between the object and the disk is 0.087.

Explanation:

According to the statement, the object on the disk experiments a centrifugal force due to static friction. From 2nd Newton's Law, we can represent the object by the following formula:

\Sigma F_{r} = \mu_{s}\cdot N = m\cdot \frac{v^{2}}{R} (1)

\Sigma F_{y} = N - m\cdot g = 0 (2)

Where:

N - Normal force from the ground on the object, measured in newtons.

m - Mass of the object, measured in newtons.

g - Gravitational acceleration, measured in meters per square second.

v - Linear speed of rotation of the disk, measured in meters per second.

R - Distance of the object from the center of the disk, measured in meters.

By applying (2) on (1), we obtain the following formula:

\mu_{s}\cdot m\cdot g = m\cdot \frac{v^{2}}{R}

\mu_{s} = \frac{v^{2}}{g\cdot R}

If we know that v = 0.8\,\frac{m}{s}, g = 9.807\,\frac{m}{s^{2}} and R = 0.75\,m, then the coefficient of static friction between the object and the disk is:

\mu_{s} = \frac{\left(0.8\,\frac{m}{s} \right)^{2}}{\left(9.807\,\frac{m}{s^{2}} \right)\cdot (0.75\,m)}

\mu_{s} = 0.087

The coefficient of static friction between the object and the disk is 0.087.

5 0
3 years ago
Which statement is correct?
NISA [10]

Answer:

1st statement is true

Explanation:

Here statement 1 is correct

Let think about it, if you push down the bar then you are lifting your weight off the pedals.

Obviously, this question does not take into account of racing bikes with straps on pedals, where you would push on one side and pull on the other to match your legs are doing, with straps your other leg can pull pedals upward.

5 0
3 years ago
Why the sun emits most of its energy in the form of visible light?
I am Lyosha [343]

Human eye could perceive this visible light and used it to look at the objects.

<u>Explanation: </u>

There are 3 forms of radiation emitted by the sun. They are Infrared radiation, Ultra Violet radiation as well as visible radiation.

Visible light is the type of light can perceive by the human eye and utilizes to see the objects.  

Since the sun is hotter (5800 K) than the earth, it emits mostly the radiation energy in the form of this visible light.

8 0
3 years ago
Two golf balls are hit from the same point on a flat field. Both are hit at an angle of 20° above the horizontal. Ball 2 has twi
Nutka1998 [239]

Answer:

E) d_{2} = 4d_{_{1}}

Explanation:

We know that the range of a projectile is given by:

R=\frac{u^2.sin\ \2\theta}{g}

where:

u = initial velocity of the projectile

\theta = angle of projection of projectile

<u>Now, range for ball 1 :</u>

d_1=\frac{u^2.sin\ \2\theta}{g}

<u>Now, range for ball 2 with double velocity and all the other parameters being the same:</u>

d_2=\frac{(2u)^2.sin\ \2\theta}{g}

d_2=4\times \frac{u^2.sin\ \2\theta}{g}

d_2=4\times d_1

5 0
3 years ago
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