I would say that the answer would be MASS.
Answer:
only thing I think of when I see that is 'Just Wondering'
Explanation:
Answer:
![13 W/m^2](https://tex.z-dn.net/?f=13%20W%2Fm%5E2)
Explanation:
The apparent brightness follows an inverse square law, therefore we can write:
![I \propto \frac{1}{r^2}](https://tex.z-dn.net/?f=I%20%5Cpropto%20%5Cfrac%7B1%7D%7Br%5E2%7D)
where I is the apparent brightness and r is the distance from the Sun.
We can also rewrite the law as
(1)
where in this problem, we have:
apparent brightness at a distance
, where
million km
We want to estimate the apparent brightness at
, where
is ten times
, so
![r_2 = 10 r_1](https://tex.z-dn.net/?f=r_2%20%3D%2010%20r_1)
Re-arranging eq.(1), we find
:
![I_2 = \frac{r_1^2}{r_2^2}I_1 = \frac{r_1^2}{(10r_1)^2}(1300)=\frac{1}{100}(1300)=13 W/m^2](https://tex.z-dn.net/?f=I_2%20%3D%20%5Cfrac%7Br_1%5E2%7D%7Br_2%5E2%7DI_1%20%3D%20%5Cfrac%7Br_1%5E2%7D%7B%2810r_1%29%5E2%7D%281300%29%3D%5Cfrac%7B1%7D%7B100%7D%281300%29%3D13%20W%2Fm%5E2)
There are no appropriate units for power on the list you provided