Answer:
a = 0.009 J
b = 0.19 m/s
c = 0.005 J and 0.004 J
Explanation:
Given that
Mass of the object, m = 0.5 kg
Spring constant of the spring, k = 20 N/m
Amplitude of the motion, A = 3 cm = 0.03 m
Displacement of the system, x = 2 cm = 0.02 m
a
Total energy of the system, E =
E = 1/2 * k * A²
E = 1/2 * 20 * 0.03²
E = 10 * 0.0009
E = 0.009 J
b
E = 1/2 * k * A² = 1/2 * m * v(max)²
1/2 * m * v(max)² = 0.009
1/2 * 0.5 * v(max)² = 0.009
v(max)² = 0.009 * 2/0.5
v(max)² = 0.018 / 0.5
v(max)² = 0.036
v(max) = √0.036
v(max) = 0.19 m/s
c
V = ±√[(k/m) * (A² - x²)]
V = ±√[(20/0.5) * (0.03² - 0.02²)]
V = ±√(40 * 0.0005)
V = ±√0.02
V = ±0.141 m/s
Kinetic Energy, K = 1/2 * m * v²
K = 1/2 * 0.5 * 0.141²
K = 1/4 * 0.02
K = 0.005 J
Potential Energy, P = 1/2 * k * x²
P = 1/2 * 20 * 0.02²
P = 10 * 0.0004
P = 0.004 J
Answer:
4.80 seconds
Explanation:
The velocity of sound is obtained from;
V= 2d/t
Where;
V= velocity of sound = 329.2 ms-1
d= distance from the wall = 790.5 m
t= time = the unknown
t= 2d/V
t= 2 × 790.5/ 329.2
t= 4.80 seconds
Imma guess A! Idk if it’s 100% correct tho so I’d check that!
<u>Hello and Good Morning/Afternoon</u>:
<em>Original Question: C₂H₅OH + __O₂ → __CO₂ + __ H₂O</em>
<u>To balance this equation</u>:
⇒ must ensure that there is an equal number of elements on both sides of the equation at all times
<u>Let's start balancing:</u>
- On the left side of the equation, there are 2 carbon molecule
⇒ but only so far one on the right side
C<em>₂H₅OH + __O₂ → 2CO₂ + __ H₂O</em>
- On the left side of the equation, there are 6 hydrogen molecules
⇒ but only so far two on the right side
C<em>₂H₅OH + __O₂ → 2CO₂ + 3H₂O</em>
- On the right side of the equation, there are 7 oxygen molecules
⇒ but only so far three on the left side
C<em>₂H₅OH + 3O₂ → 2CO₂ + 3H₂O</em>
<u>Let's check and make sure we got the answer:</u>
C<em>₂H₅OH + 3O₂ → 2CO₂ + 3H₂O</em>
<em> 2 Carbon ⇔ 2 Carbon</em>
<em> 6 Hydrogen ⇔ 6 Hydrogen</em>
<em> 7 Oxygen ⇔ 7 oxygen</em>
<u>Thefore the coefficients in order are</u>:
⇒ 1, 3, 2, 3
<u>Answer: 1,3,2,3</u>
Hope that helps!
#LearnwithBrainly<em> </em>
