Answer:
8.33 atm
Explanation:
Xe is 5 out of (4+5) or 5 / 9 ths of the gas present
5/9 * 15 atm = 8.33 atm
Answer:
The system makes the transition from nonspontaneous to spontaneous at a temperature of 954.7 K.
Under 954.7 K the reaction is nonspontaneous; more than 954.7 K is the reaction spontaneous.
Explanation:
CH4(g) + 2H2O(g) ⇆ CO2(g) + 4H2(g)
CH4(g) H2O(g) CO2(g) H2(g) ΔH°f (kJ/mol): –74.87 –241.8 –393.5 0
ΔG°f (kJ/mol): –50.81 –228.6 –394.4 0
S°(J/K·mol): 186.1 188.8 213.7 130.7
ΔG<0 to be spontaneous
ΔG = ΔH- TΔS <0
ΔH = ∑nΔH(products) - ∑nΔH(reactant)
ΔH = (-393.5) - (–74.87 + 2*–241.8)
ΔH = 164.97 kJ = 164970 J
ΔS = ∑nΔS(products) - ∑nΔS(reactant)
ΔS = (213.7 + 4*130.7) - (186.1 + 2*188.8)
ΔS = 172.8 J
0 > 164970 J - T* 172.8 J
-164970 J > - T* 172.8 J
954.7< T
The system makes the transition from nonspontaneous to spontaneous at a temperature of 954.7 K.
Under 954.7 K the reaction is nonspontaneous; more than 954.7 K is the reaction spontaneous.
Answer:
The answer would be, B. water
Explanation:
If I remember correctly, an abiotic factor is a nonliving condition or thing, as climate or habitat, that influences or affects an ecosystem and the organisms in it. This would make water, the most accurate choice.
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Answer:
So ²³⁵UF₆ effuses 1.0043 times faster than ²³⁸UF₆
Explanation:
The rate of effusion of two gases A and B can be expressed by <em>Graham's law</em>:
Where M is the molar mass, and in this case A is ²³⁵UF₆ while B is ²³⁸UF₆.
So now we <u>calculate the molar mass of each mass</u>:
²³⁵UF₆ ⇒235 + 6*19 = 349 g/mol
²³⁸UF₆ ⇒238 + 6*19 = 352 g/mol
Putting the data in Graham's law:
= 1.0043
So ²³⁵UF₆ effuses 1.0043 times faster than ²³⁸UF₆.