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3 years ago

Which reaction is an example of a precipitation reaction?

Chemistry

2 answers:

DENIUS [597]3 years ago

8 0

Answer: Option (A) is the correct answer.

Explanation:

When two aqueous solutions chemically combine together then there is a possibility that an insoluble solid substance might form. This insoluble substance is known as a precipitate and this type of reaction is known as precipitation reaction.

For example, $FeCl_{3}(aq) + 3KOH(aq) \rightarrow Fe(OH)_{3}(s) + 3KCl(aq)$

Here, $Fe(OH)_{3}(s)$ is the precipitate.

Thus, we can conclude that out of the given options, the reaction $FeCl_{3}(aq) + 3KOH(aq) \rightarrow Fe(OH)_{3}(s) + 3KCl(aq)$ is an example of a precipitation reaction.

Klio2033 [76]3 years ago

3 0

Answer:

(A) FeCl3 (aq) + 3 KOH (aq) → Fe(OH)3 (s) + 3 KCl (aq)

Explanation:

A precipitation reaction happens when a solid (called a precipitate) is formed due the reaction between anions and cations that were previously in aqueous solution.

In B there were no cations or anions that interacted

In C, and D, cations and anions interacted but no solid (precipitate was formed)

In E the cations interacted with a solid and no precipitate was formed.

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In the formula for the compound XCl4, the X could represent (1) C (3) Mg (2) Η (4) Zn

Anvisha [2.4K]

Correct Answer: option 1 i.e. C

Reason:
The the compound of interest i.e. XCl4, since there are 4 Cl atoms bonded to X. This signifies that the valency of X is 4.

There atomic number of C is 6. It's electronic configuration is giving by 1s2 2s2 2p2. Thus, there are 4 electrons in valence shell of C. This signifies that valency of C is 4. Hence the compound present in present case is CCl4.

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4 years ago

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Question:

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3 years ago

When the equation Sn + HNO₃ → SnO₂ + NO₂ + H₂O is balanced in acidic solution, what is the smallest whole-number coefficient for

balu736 [363]

Answer:

Explanation:

Hello,

In this case, for the given reaction we first assign the oxidation state for each species:

$Sn^0 + H^+N^{5+}O^{-2}_3 \rightarrow Sn^{4+}O_2 + N^{4+}O^{2-}_2 + H^+_2O^-$

Whereas the half reactions are:

$Sn^0+2H_2O \rightarrow Sn^{4+}O_2 +4H^++4e^-\\\\H^++H^+N^{5+}O^{-2}_3 +1e^-\rightarrow N^{4+}O^{2-}_2+H_2O$

Next, we exchange the transferred electrons:

$1\times(Sn^0+2H_2O \rightarrow Sn^{4+}O_2 +4H^++4e^-)\\\\4\times (H^++H^+N^{5+}O^{-2}_3 +1e^-\rightarrow N^{4+}O^{2-}_2+H_2O)\\\\\\Sn^0+2H_2O \rightarrow Sn^{4+}O_2 +4H^++4e^-\\\\4H^++4H^+N^{5+}O^{-2}_3 +4e^-\rightarrow 4N^{4+}O^{2-}_2+4H_2O$

Afterwards, we add them to obtain:

$Sn^0+2H_2O+4H^++4H^+N^{5+}O^{-2}_3 \rightarrow Sn^{4+}O_2 +4H^++4N^{4+}O^{2-}_2+4H_2O$

By adding and subtracting common terms we obtain:

$Sn^0+4H^+N^{5+}O^{-2}_3 \rightarrow Sn^{4+}O_2 +4N^{4+}O^{2-}_2+2H_2O$

Finally, by removing the oxidation states we have:

$Sn + 4HNO_3 \rightarrow SnO_2 + 4NO_2 + 2H_2O$

Therefore, the smallest whole-number coefficient for Sn is 1.

Regards.

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3 years ago

What is the best conclusion according to the energy diagram of the chemical reaction?

Mariulka [41]

"The reaction will absorb energy" is the best conclusion according to the energy diagram of the chemical reaction.

Option: B

Explanation:

The chemical bonds in the reactions are broken and formed as per process and contributed by three major steps: reactants, transition phase and product formation. Here transition phase is in equilibrium stage drived by activation energy, where bond is partially formed and partially broken, located at higher energy level then the starters.

The reactant's energy level is less relative to the products as seen in the endothermic reactions' energy diagram, which depicts that the products are less balanced than reactants. Here when the reaction is forced to the forward direction, then it direct towards the more unbalance entities. As energy is absorbed in the endothermic reaction from surrounding, thus the enthalpy change (ΔH) for the reaction is positive.

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3 years ago

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SCORPION-xisa [38]

Answer:

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Explanation:

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