The empirical and molecular formula would be and
respectively.
The compound contains N and O.
N O
0.608/14 = 0.0434 1.388/16 = 0.0867
Divide by the smallest.
N = 1 O = 2
Thus, the empirical formula would be
To get the molecular formula:
Empirical formula mass = 14 + (16x2) = 46
n = molar mass/empirical formula mass
= 92/46 = 2
Thus, the molecular formula would be
More on empirical formulas can be found here: brainly.com/question/14044066
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Answer:
- Take 3.3 mL of 3.0-M hydrochloric acid and subsequently add 76.7 mL of water to complete the 100.00 mL.
- Take 11.7mL of 6.0-M hydrochloric acid and subsequently add 88.3 mL of water to complete the 100.00 mL
Explanation:
Hello,
In this case, given that the dilutions are preparedfrom 3.0-M and 6.0-M hydrochloric acid, we must proceed as follows:
- 3.0-M stock: when using this stock, the aliquot you must take is computed as shown below:
It means that you must take 23.3 mL of 3.0-M hydrochloric acid and subsequently add 76.7 mL of water to complete the 100.00 mL.
- 6.0-M stock: when using this stock, the aliquot you must take is computed as shown below:
It means that you must take 11.7mL of 6.0-M hydrochloric acid and subsequently add 88.3 mL of water to complete the 100.00 mL.
Regards.