Answer:
38
Explanation:
that I believe is correct
When the concentration is expressed in molality, it is expressed in moles of solute per kilogram of solvent. Since we are given the mass of the solvent, which is water, we can compute for the moles of solute NaNO3.
0.5 m = x mol NaNO3/0.5 kg water
x = 0.25 mol NaNO3
Since the molar mass of NaNO3 is 85 g/mol, the mass is
0.25 mol * 85 g/mol = 21.25 grams NaNO3 needed
Based on experiment 1:
Mass of Hg = 1.00 g
Mass of sulfide = 1.16 g
Mass of sulfur = 1.16 - 1.00 = 0.16 g
# moles of Hg = 1 g/200 gmol-1 = 0.005 moles
# moles of S = 0.16/32 gmol-1 = 0.005 moles
The Hg:S ratio is 1:1, hence the sulfide is HgS
Based on experiment 2:
Mass of Hg taken = 1.56 g
# moles of Hg = 1.56/200 = 0.0078
Mass of S taken = 1.02 g
# moles of S = 1.02/32 = 0.0319
Hence the limiting reagent is Hg
# moles of Hg reacted = # moles of HgS formed = 0.0078 moles
Molar mass of HgS = 232 g/mol
Therefore, mass of HgS formed = 0.0078 * 232 = 1.809 g = 1.81 g
Answer:
Remove your shirt and any other clothing that were in contact with the chemical
Explanation:
A hazardous chemical has the capacity to cause damage to the body when it comes in contact with the skin. Many hazardous chemicals are capable of being absorbed into the body via the skin.
Once your lab coat is already doused with the chemical and it has started soaking into you clothing, you must remove your lab coat, shirt and all clothing that were in contact with the hazardous chemical as a safety measure to avoid absorption of the chemical into the body via the skin. Some of these chemicals also cause damages directly to the skin and this must be avoided.
