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2 years ago

8

Zeros that follow non-zero numbers and are also to the right of a decimal point are significant.

2 answers:

storchak [24]2 years ago

6 0

Yes that's correct.also zeros in between non-zero numbers are significant figures

Ivenika [448]2 years ago

5 0

Yes that's correct. Also zeros in between non-zero numbers are significant figures

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A string is wrapped around a uniform disk of mass M = 1.2 kg and radius R = 0.07 m. (Recall that the moment of inertia of a unif

pentagon [3]

Explanation:

Given that,

Mass of disk = 1.2 kg

Radius = 0.07 m

Radius of rod = 0.11 m

Mass of small disk = 0.5 kg

Force = 29 N

Time t = 0.022 s

$\theta=0.023\ m$

Distance d= 0.039 m

(I). We need to calculate the speed of the apparatus

Using work energy theorem

$W=\Delta K.E$

$Fd=\dfrac{1}{2}mv^2$

$v=\sqrt{\dfrac{2Fd}{M+4m}}$

Where, m = total mass

v = velocity

F = force

d = distance

Put the value into the formula

$v=\sqrt{\dfrac{2\times29\times0.039}{1.2+4\times0.5}}$

$v=0.840\ m/s$

(b). We need to calculate the angular speed of the apparatus

Using formula of torque

$\tau=I\alpha$

$F\times=(\dfrac{1}{2}MR^2+4mb^2)\alpha$

$29\times0.07=(\dfrac{1}{2}\times1.2\times0.07^2+4\times0.5\times0.11^2)\alpha$

$\alpha=\dfrac{29\times0.07}{0.02714}$

$\alpha=74.79\ rad/s^2$

We need to calculate the angular speed of the apparatus

Using equation of angular motion

$\omega=\omega_{0}+\alpha t$

Put the value into the formula

$\omega=0+74.79\times0.022$

$\omega=1.645\ rad/s$

(c). We need to calculate the angular speed of the apparatus

Using equation of angular motion

$\omega_{0}^2=\omega^2+2\alpha t$

Put the value into the formula

$\omega_{0}^2=1.645^2+2\times74.79\times0.022$

$\omega=2.44\ rad/s$

Hence, This is required equation.

7 0

2 years ago

How do cells and atoms relate?

Aleks [24]

A cell is made up of molecules and molecule is made up of atoms. So, they both need molecules to be made.

5 0

3 years ago

Read 2 more answers

Consider the nearly circular orbit of Earth around the Sun as seen by a distant observer standing in the plane of the orbit. Wha

ikadub [295]

We have that the spring constant is mathematically given as

$k=2.37*10^{11}N/m$

Generally, the equation for angular velocity is mathematically given by

$\omega=\sqrt{k}{m}$

Where

k=spring constant

And

$\omega =\frac{2\pi}{T}$

Therefore

$\frac{2\pi}{T}=\sqrt{k}{n}$

Hence giving spring constant k

$k=m((\frac{2 \pi}{T})^2$

Generally

Mass of earth $m=5.97*10^{24}$

Period for on complete resolution of Earth around the Sun

$T=365 days$

$T=365*24*3600$

Therefore

$k=(5.97*10^{24})((\frac{2 \pi}{365*24*3600})^2$

$k=2.37*10^{11}N/m$

In conclusion

The effective spring constant of this simple harmonic motion is

$k=2.37*10^{11}N/m$

For more information on this visit

brainly.com/question/14159361

8 0

2 years ago

2. An alternating current is represented by the equation I=20sin 100mt.

Sladkaya [172]

Explanation:

The general equation of an AC current is given by :

$I=I_o sin\omega t$

Where

I₀ is the peak value of current

$\omega$ is angular frequency

$As\ \omega=2\pi f$

So,

$f=\dfrac{\omega}{2\pi}\\\\f=\dfrac{100\pi}{2\pi}\\\\f=50\ Hz$

We know that,

$I_{rms}=\dfrac{I_0}{\sqrt{2}}\\\\=\dfrac{20}{\sqrt{2}}\\\\I_{rms}=14.14\ A$

So, the frequency is 50 Hz and the maximum rms value of current is 14.14 A.

3 0

2 years ago

A suitcase (mass m = 18 kg) is resting on the floor of an elevator. The part of the suitcase in contact with the floor measures

Sindrei [870]

Answer:

P=2736 Pa

Explanation:

According to Newton we have that:

∑ $F=m*a\\$

A force is exerted by the elevator to the suitcase, according to 3th Newton's law an equal force but in the opposite direction will appeared on the suitcase, that is:

∑ $F=m*g+m*a=m*(g+a)$

$F=205.2N$

We know that the pressure is given by:

$P=\frac{F}{A}\\P=\frac{205.2N}{(0.50m)*(0.15m)}\\P=2736N/m^2=2736Pa$

6 0

2 years ago