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DENIUS [597]
3 years ago
12

What is the relationship between volume and pressure for a gas?

Chemistry
1 answer:
QveST [7]3 years ago
8 0

Answer:

There exists a relationship between pressure and volume through Boyle's Law. It states that when temperature is held constant in thermodynamic syatems, the volume increases as the pressure decreases (and is true the other way around).

<em>Hope</em><em> this</em><em> helps</em><em> </em><em>:</em><em>)</em>

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One sphere has a radions of 181 cm, another has a radius of 5.01 cm. What is the difference in volume (in cubic centimeters) bet
PSYCHO15rus [73]

Answer:

2.4*10^{7}cm^{3}

Explanation:

First you should calculate the volume of a big sphere,so:

V_{big}=\frac{4}{3}\pi r^{3}

V_{big}=\frac{4}{3}\pi (181cm)^{3}

V_{big}=2.4*10^{7}cm^{3}

Then you calculate the volume of a small spehre, so:

V_{small}=\frac{4}{3}\pi r^{3}

V_{small}=\frac{4}{3}\pi (5.01cm)^{3}

V_{small}=5.3*10^{2}cm^{3}

Finally you subtract the two quantities:

V_{big}-V_{small}=2.4*10^{7}cm^{3}-5.3*10^{2}cm^{3}

V_{big}-V_{small}=2.4*10^{7}cm^{3}

5 0
3 years ago
When balancing equations does po4 counts as one element or on p and 4 o?
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3 0
4 years ago
Read 2 more answers
What is orbital theory of bonding in metals
lianna [129]
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3 years ago
What is the electric field (in N/C) at a point 5.0 cm from the negative charge and along the line between the two charges?
Natali [406]

Answer: E = 2.455 x 10^5 N/C

Explanation:

q1 = 1.2x10^-7C

q2 = 6.2x10^-8C

Electric field, E = kQ/r²

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since the location is (27 - 5)cm from q1

hence electric field, E1 = k*q1/r²

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for q2:

E1 = k*q2/r²

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E2 = (9x10^9 x 6.2x10^-8)/(0.05)² = 223200 N/C

Hence, the total electric field at 5cm position is

E = E1 + E2

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E = 2.455 x 10^5 N/C

4 0
3 years ago
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