3 years ago

Can you use molecular orbital theory to explain why fluorine is such a highly reactive gas?

1 answer:

7 0

The F2 molecular orbital diagram shows 4e- are in the highest energy antibonding (destabilizing) molecular orbitals resulting in a bond order = 1.

Single bonds are easier to break and therefore more reactive. So the answer is yes.

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Answer:

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$t=\dfrac{ln(\dfrac{N}{N_0})t_\frac{1}{2} }{-0.693}$

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