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3 years ago

PLEASE HELP!!

Physics

1 answer:

kolezko [41]3 years ago

3 0

ATOMIC MASS- 3

PROTONS- 1

NEUTRONS- 4

ISOTOPE- 5

ATOMIC NUMBER- 2

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Look at the illustration , what concepts of heat are being shown in this pictures <br>

Phoenix [80]

<h2> (っ◔◡◔)っ ♥ Hey Honey Here<em>!</em> ♥</h2>

Answer:

♥ Convection.

♥ Conduction.

♥ Radiation.

♥ ( お力になれて、嬉しいです！) ♥

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3 years ago

The tip of the second hand of a clock moves in a circle of 20 cm circumference. In one minute the hand makes a complete revoluti

Cerrena [4.2K]

Answer:

$v_{avg} = 0$

Explanation:

As we know that average velocity is defined as the ratio of total displacement of the object and its time interval.

so here we can say

$v_{avg} = \frac{displacement}{time}$

now we know that in one complete revolution the total displacement of the tip of the seconds hand is zero

because it will have same position after one complete revolution from where it starts

so here we can say that the average velocity will be zero

$v_{avg} = 0$

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3 years ago

bumper car A (281 kg) moving +2.82 m/s makes an elastic collision with bumper car B (209 kg) moving +1.72 m/s what is the veloci

spin [16.1K]

Answer: V1 = 3.559 - 0.744V2

Explanation: Given that the

bumper car A has

Mass M1 = (281 kg) moving with

Velocity U1 = 2.82 m/s

bumper car B has

Mass M2 = (209 kg) moving with

Velocity U2 = 1.72 m/s

Where U1, U2 are the initial velocity of the two cars

Since the collision is elastic, we will use the formula below,

M1U1 + M2U2 = M1V1 + M2V2

Substitute the values into the formula

281×2.28 + 209×1.72 = 281V1 + 209V2

640.68 + 359.48 = 281V1 + 209V2

1000.16 = 281V1 + 209V2

Make V1 the subject of formula

281V1 = 1000.16 - 209V2

V1 = 1000.16/281 - 209V2/281

V1 = 3.559 - 0.744V2

Therefore, the velocity of car A which

is V1 after the collision will be expressed as V1 = 3.559 - 0.744V2

6 0

3 years ago

A child whose weight is 276 N slides down a 5.90 m playground slide that makes an angle of 34.0° with the horizontal. The coeffi

garik1379 [7]

Answer:

Explanation:

Frictional force acting on the child = μ mg cosθ

, μ is coefficient of kinetic friction , m is mass of child θ is inclination

work done by frictional force

μ mg cosθ x d , d is displacement on inclined plane

work done = .13 x 276 x cos34 x 5.9

= 175.5 J

This work will be converted into heat energy.

b ) Initial energy of child = mgh + 1/2 m v ² , h is height , v is initial velocity

= 276 x 5.9 sin34 + 1/2 x 276 / 9.8 x .518² [ mass m = 276 / g ]

= 910.59 + 3.77

= 914.36 J

loss of energy due to friction = 175.5

Net energy at the bottom

= 738.86 J

If v be the velocity at the bottom

1/2 m v² = 738 .86

.5 x (276 / 9.8) x v² = 738.86

v² = 52.47

v = 7.24 m /s .

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3 years ago

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Please help It is Anatomy and Phys

kap26 [50]

Answer:

the last time i had my tempature taken was at disney prings about a week ago -_- they used one of those gun things that dont touch u and the SHOVED me forward so i guess i was fine

Explanation:

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2 years ago

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