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3 years ago

PLEASE HELP!!

Physics

1 answer:

kolezko [41]3 years ago

3 0

ATOMIC MASS- 3

PROTONS- 1

NEUTRONS- 4

ISOTOPE- 5

ATOMIC NUMBER- 2

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Answer:

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2 years ago

Tires of a Bigfoot truck has a diameter of 2.2 m. If it rotates 60 revolutions find distance travel on the road.

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Answer:

$s = 414.7 m\\$

Explanation:

The relationship between the linear distance covered by an object and its angular displacement is given by the following formula:

s = rθ

where,

s = distance traveled on road = ?

r radius of tires = diameter/2 = 2.2 m/2 = 1.1 m

θ = angular displacement = (60 rev)(2π rad/1 rev) = 377 rad

Therefore,

$s = (1.1 m)(377 rad)\\s = 414.7 m$

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2 years ago

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2 years ago

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We are sending a 30 Mbit file from source host A to destination host B. All links in the path between source and destination hav

Dmitrij [34]

Answer:

$t=1.5\times 10^{-4}\ s$

Explanation:

Given:

file size to be transmitted, $D=30\ Mb$

transmission rate of data, $\dot D=10\ Mb.s^{-1}$

propagation speed, $v=2\times 10^8\ m.s^{-1}$

distance of data transfer, $s=10000\ km=10^4\ m$

<u>Now the delay in data transfer from source to destination for each 10 Mb:</u>

$t'=\frac{s}{v}$

$t'=\frac{10^4}{2\times 10^8}$

$t'=5\times 10^{-5}\ s$

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So,

$t=3\times t'$

$t=3\times 5\times 10^{-5}$

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2 years ago

What is a cars acceleration in the direction of motion when velocity changes from 20. M/s to 60. M/s in 10. S

brilliants [131]

Answer:

Acceleration, $a=4\ m/s^2$

Explanation:

Given that,

Initial velocity, u = 20 m/s

Final velocity, v = 60 m/s

Time, t = 10 s

We need to find the acceleration of the car. It is equal to the change in velocity divided by time.

$a=\dfrac{v-u}{t}\\\\a=\dfrac{60-20}{10}\\\\a=\dfrac{40}{10}\\\\a=4\ m/s^2$

So, the acceleration of the car is $4\ m/s^2$ .

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2 years ago