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Nataly [62]
4 years ago
5

PLEASE HELP!!

Physics
1 answer:
kolezko [41]4 years ago
3 0

ATOMIC MASS- 3

PROTONS- 1

NEUTRONS- 4

ISOTOPE- 5

ATOMIC NUMBER- 2

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Explanation:

Galaxies are moving closer

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An electric motor is used to run an elevator. The total mass of the elevator car and passenger is 1600 kg. The elevator moves up
Masja [62]

Answer:

Approximately 2.7 \times 10^{4}\; {\rm W}, assuming that g = 9.81\; {\rm m\cdot s^{-2}}

Explanation:

The weight of the elevator is:

\begin{aligned}& \text{weight} \\ =\; & m\, g \\ =\; & 1600\; {\rm kg} \times 9.81\; {\rm m \cdot s^{-2}} \\ \approx\; & 15700\; {\rm N}\end{aligned}.

Since the speed of the elevator is constant, the acceleration of this elevator would be 0.

By Newton's Second Law of Motion, the net force on the elevator (proportional to acceleration) would also be 0\!. All external forces on the elevator need to be balanced in every direction.

The only two vertical forces on the elevator are:

  • the weight of the elevator (downward gravitational pull from the earth,) and
  • the upward pull from the motor.

These two forces need to balance one another. Since the weight of the elevator is approximately 15700\; {\rm N}, the upward pull of the motor would be 15700\; {\rm N}\!. in magnitude.

The direction of this upward pull is the same as the direction of the motion of this elevator. Thus, the work that the motor did on the elevator would be positive:

\begin{aligned}& \text{work} \\ =\; & F\, s \\ \approx\; & 15700\; {\rm N} \times 15.0\; {\rm m} \\ \approx\; & 2.35 \times 10^{5}\; {\rm J}\end{aligned}.

Since the velocity of the elevator is constant, instantaneous power output of the motor would be equal to the average power of the motor:

\begin{aligned}& \text{power} \\ =\; & \frac{\text{work}}{t} \\ \approx\; & \frac{2.35 \times 10^{5}\; {\rm J}}{8.82\; {\rm s}} \\ \approx\; & 2.7 \times 10^{4}\end{aligned}.

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3 years ago
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Paraphin [41]

Answer:

B I think

Explanation:

hope this helped!

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For the A groups (Groups 1A to 8A), how does the group number relate to the electron arrangement in atoms of the group?
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Answer;

D. The group number is equal to the number of valence electrons.

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-For neutral atoms, the number of valence electrons is equal to the atom’s main group number.

Number of valence electrons = main group number (neutral atoms)

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