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3 years ago

How do you answer this. Need help ASAP. Offering 20 points !!!

Physics

1 answer:

Temka [501]3 years ago

7 0

in this since your volume remains at a constant you'll need to use Gay-Lussacs law, p1/t1=p2/t2.

your temp should be converted in kelvin

variables:

p1=3.0×10^6 n/m^2

t1= 270k

just add 273 to your celcius

p2= ? your solving for this

t2= 315k

then you set up the equation

(3.0×10^6)/270= (x)(315)

you then cross multiply

(3.0×10^6)315=270x

distribute the 315 to the pressure.

9.45×10^8=270x then you divide 270 o both sides to get

answer

3.5×10^6 n/m^2

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(b) 5.056 x 10^-14 N

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charge on electron, q = - 1.6 x 10^-19 C

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$\overrightarrow{v}=1.6\times 10^{6}\widehat{i}+2.4\times 10^{6}\widehat{j}$

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$\overrightarrow{F}=-1.6\times 10^{-19}\left ( 1.6\times 10^{6}\widehat{i}+2.4\times 10^{6}\widehat{j} \right )\times \left ( 0.025\widehat{i}-0.16\widehat{j} \right )$

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Magnitude of force is 5.056 x 10^-14 N.

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$\overrightarrow{F}=1.6\times 10^{-19}\left ( 1.6\times 10^{6}\widehat{i}+2.4\times 10^{6}\widehat{j} \right )\times \left ( 0.025\widehat{i}-0.16\widehat{j} \right )$

$\overrightarrow{F}=-5.056\times 10^{-14}\widehat{k}$

Magnitude of force is 5.056 x 10^-14 N.

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