In a copper wire, the flow of current is made up of which of the following?
2 answers:
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Answer:
The velocity of motion at which the occupants of the car appear to weigh 20% less than their normal weight is approximately 19.81 m/s
Explanation:
The given parameters are;
The curvature of the hill, r = 200 m
Due to the velocity, v, the occupants weight = 20% less than the normal weight
The outward force of an object due to centripetal (motion) force is given by the following equation;
Where;
r = The radius of curvature of the hill = 200 m
Given that the weight of the occupants, W = m × g, we have;
v = √(0.2 × g × r)
By substitution, we have;
v = √(0.2 × 9.81 × 200) ≈ 19.81
The velocity of motion at which the occupants of the car appear to weigh 20% less than their normal weight ≈ 19.81 m/s.
Answer:
Both rod have the same tensile stress
Explanation:
Given information,
The weight first rod, = 1000 N
The length of first rod, = 2.0 m
The weight second rod, = 500 N
The length of second rod, = 1.0 m
The equation of tensile stress, σ =
where
σ = tensile stress (N/ or Pa)
F = Force (N)
A = Area (N/ or Pa)
so
σ1 = , A = 2πl
=
= N/
now calculate σ2
σ2 =
=
= N/
σ1/σ2 = /
σ1/σ2 = 1
σ1 = σ2
Hence, the tensile stress of first and second rod are the same.