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Ksivusya [100]
3 years ago
6

In a 1.0x10^-4 M solution of HClO(aq), identify the relative molar amounts of these species:HClO, OH-, H3O+, OCl-, H2O

Chemistry
2 answers:
Fantom [35]3 years ago
7 0

The Formula is:

Molar Mass of an Element = x Relative mass of atoms Molar mass constant (1g / mol)

<h2>Further Explanation </h2><h3>Understand molar mass </h3>

Molar mass = mass (in grams) of 1-mol substances

Molar mass is the mass (in grams) of one mole of a substance. By using the atomic mass of an element and multiplying it by the conversion factor of grams per mole (g / mol), you can calculate the molar mass of the element.

<h3>Look for the relative atomic mass of elements </h3>

Relative atomic mass:

Hydrogen = 1,007

Carbon = 12.0107

Oxygen = 15,9994

Chlorine = 35,453

The relative atomic mass of an element is the average mass of a sample of all its isotopes in atomic units. This information can be found in the periodic table of elements.

<h3>Multiply the atomic mass relative to the molar mass constant </h3>

Molar Mass of an Element = x Relative mass of atoms Molar mass constant (1g / mol)

Hydrogen = 1,007 x 1g / mol = 1,007 g / mol

Carbon = 12.0107 g / mol

Oxygen = 15,999 g / mol

Chlorine = 35,453 g / mol

H2: 1,007 x 2 = 2,014 g / mol

O2: 15,999 x 2 = 31,9988 g / mol

C2: 35,453 x 2 = 70,096 g / mol

<em>example: </em>

Hydrochloric acid

HCl -> 1 hydrogen atom, 1 chlorine atom

Glucose

C6H12O6 -> 6 carbon atoms, 12 hydrogen atoms, 6 oxygen atoms

Learn More

Molar mass brainly.com/question/2194946

Calculate molar mass brainly.com/question/11444952

Details

Class: Middle/High School

Subject: Chemistry

Keywords: Mass, Molar, atoms

yarga [219]3 years ago
6 0
HClO is a weak acid, which means the ions do not fully dissociate. The hydrolysis reaction for the hypochlorous acid is:

HClO + H2O ⇄ H3O+ +OCl-

Then the equilibrium constant, Ka, of dilute HClO would be:

K_{a} = \frac{[ H_{3}  O^{+} ][O Cl^{-} ]}{HClO}

Then we do the ICE table. I is for the initial concentration, C for the change and E for the excess.
      
          HClO       + H2O   ⇄   H3O+ +  OCl-
I     1.0x10^-4                          0             0
C        -x                                 +x           +x 
E  (1.0x10^-4 - x)                     x             x

Substituting the excess (E) concentration to the Ka equation:

K_{a} = \frac{[x ][x]}{1.0 \ x \  10^{-4} - x }

Simplifying the equation would yield a quadratic equation:

x^{2} + K_{a}x-(1.0 \ x \ 10^{-4}) K_{a}=0

The Ka for HClO is an experimental data which was determined to be 2.9 x 10^-8. Substitute this to the equation, determine the roots, then you get the value for x, which is the concentration of H3O+ and ClO-. Just use your calculator feature Shift-Solve.

x = 1.688 x 10^-6 M = [H3O+] = [ClO-]

Then, you can determine the conc of [OH-] through pH.

pH = -log {H3O+] = -log [1.688 x 10^-6] = 5.77
pOH = 14 - pH = 14 - 5.77 = 8.23
pOH = 8.23 = -log [OH-]
[OH-] = 5.89 x 10^-9 M

Also, since HClO is (1.0x10^-4 - x), then it's concentration would be:
[HClO] = 1.0x10^-4 - 1.688 x 10^-6 = 9.83 x10^-5 M

Let's summarize all concentrations:
[HClO] = 9.83 x10^-5 M
[OH-] = 5.89 x 10^-9 M
[H3O+] = [ClO-] = 1.688 x 10^-6 M
Since the solution is dilute, H2O is relatively higher in concentration.

Thus in relative amounts, the order would be

H2O >>> HClO > H3O+ = ClO- > OH-


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lana66690 [7]

Answer:

2, strong acid

Explanation:

Data obtained from the question. This includes:

[H+] = 0.01 M

pH =?

pH of a solution can be obtained by using the following formula:

pH = –Log [H+]

pH = –Log 0.01

pH = 2

The pH of a solution ranging between 0 and 6 is declared to be an acid solution. The smaller the pH value, the stronger the acid.

Since the pH of the above solution is 2, it means the solution is a strong acid.

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what volume of a 0.149 m potassium hydroxide solution is required to neutralize 17.0 ml of a 0.112 m hydrobromic acid solution?
IgorLugansk [536]

Answer: 12.78ml

Explanation:

Given that:

Volume of KOH Vb = ?

Concentration of KOH Cb = 0.149 m

Volume of HBr Va = 17.0 ml

Concentration of HBr Ca = 0.112 m

The equation is as follows

HBr(aq) + KOH(aq) --> KBr(aq) + H2O(l)

and the mole ratio of HBr to KOH is 1:1 (Na, Number of moles of HBr is 1; while Nb, number of moles of KOH is 1)

Then, to get the volume of a 0.149 m potassium hydroxide solution Vb, apply the formula (Ca x Va)/(Cb x Vb) = Na/Nb

(0.112 x 17.0)/(0.149 x Vb) = 1/1

(1.904)/(0.149Vb) = 1/1

cross multiply

1.904 x 1 = 0.149Vb x 1

1.904 = 0.149Vb

divide both sides by 0.149

1.904/0.149 = 0.149Vb/0.149

12.78ml = Vb

Thus, 12.78 ml of potassium hydroxide solution is required.

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I think it would lose its heat faster than the plastic bags because of higher conductivity feature.

<h3>What is conduction?</h3>

Conduction is the process in which heat or electricity is transmitted or transferred through the material of a substance without movement of the material.

We know that metals are good conductors so we can conclude that it would lose its heat faster than the plastic bags bof higher conductivity feature.

Learn more about heat here: brainly.com/question/13439286

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H2SO4 + 2 KOH --&gt; K2SO4 + 2 H2O
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Double replacement because H and K are both switching
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