First let's calculate the vertical and horizontal components of the distance:
Then, since we have the time required, let's find the speed in each direction:
Now, let's decompose the given speed in its components:
A truck on a straight road starts from rest, accelerating at 2.00 m/s2 until it reaches a speed of 48.0 m/s. Then the truck trav
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Answer:
205 m
Explanation:
We can find the time of flight of the package by considering its vertical motion first. In fact, the vertical position at time t is given by
where
h = 117 m is the initial height
is the initial vertical velocity
g = -9.8 m/s^2 is the acceleration of gravity
The package reaches the ground when y=0, so substituting this, we find the corresponding time:
Now we can find the horizontal distance travelled by the package by considering the horizontal motion only; so it is given by
where
is the horizontal velocity of the package (which is constant)
t = 4.89 s
Substituting,
So, the package lands 205 m ahead of the point directly below the plane where the package was released.