How does a kitchen sponge floating in water compare to the zone of saturation and the water table

A 2.5-L tank initially is empty, and we want to fill it with 10 g of ammonia. The ammonia comes from a line with saturated vapor

Alex17521 [72]

Answer:

592.92 x 10³ Pa

Explanation:

Mole of ammonia required = 10 g / 17 =0 .588 moles

We shall have to find pressure of .588 moles of ammonia at 30 degree having volume of 2.5 x 10⁻³ m³. We can calculate it as follows .

From the relation

PV = nRT

P x 2.5 x 10⁻³ = .588 x 8.32 x ( 273 + 30 )

P = 592.92 x 10³ Pa

3 0

2 years ago

A 2-m long string is stretched between two supports with a tension that produces a wave speed equal to vw=50.00m/s. What are the

svetoff [14.1K]

Answer

given,

Length of the string, L = 2 m

speed of the wave , v = 50 m/s

string is stretched between two string

For the waves the nodes must be between the strings

the wavelength is given by

$\lambda = \dfrac{2L}{n}$

where n is the number of antinodes; n = 1,2,3,...

the frequency expression is given by

$f = n\dfrac{v}{2L}$

now, wavelength calculation

n = 1

$\lambda_1 = \dfrac{2\times 2}{1}$

λ₁ = 4 m

n = 2

$\lambda_2 = \dfrac{2\times 2}{2}$

λ₂ = 2 m

n =3

$\lambda_3 = \dfrac{2\times 2}{3}$

λ₃ = 1.333 m

now, frequency calculation

n = 1

$f = n\dfrac{v}{2L}$

$f_1 =1\times \dfrac{50}{2\times 2}$

f₁ = 12.5 Hz

n = 2

$f = n\dfrac{v}{2L}$

$f_2 =2\times \dfrac{50}{2\times 2}$

f₂= 25 Hz

n = 3

$f = n\dfrac{v}{2L}$

$f_3 =3\times \dfrac{50}{2\times 2}$

f₃ = 37.5 Hz

8 0

2 years ago

How long can a flashlight run for if it draws 0.11 amps and its battery contains 10 coulombs of change?

Alex17521 [72]

Answer:

Battery will run for t = 90 s

Explanation:

As we know that rate of flow of charge is known as electric current

So we will have

$i = \frac{Q}{t}$

$i = 0.11 A$

$Q = 10 C$

now we have

$t = \frac{Q}{i}$

$t = \frac{10}{0.11}$

$t = 90 s$

8 0

2 years ago

Interactive Solution 11.35 presents one method for modeling this problem. Multiple-Concept Example 8 also presents an approach t

shepuryov [24]

Answer:

a) Fi = 85.76 N

b) Fi = 87.8 N

Explanation:

Given:-

- Density of hydraulic oil, ρ = 804 kg/m^3

- The radius of input piston, ri = 0.00861 m

- The radius of output piston, ro = 0.141 m

Find:-

What input force F is needed to support the 23000-N combined weight of a car and the output plunger, when

(a) the bottom surfaces of the piston and plunger are at the same level

(b) the bottom surface of the output plunger is 1.10 m above that of the input plunger?

Solution:-

For part a.

- We see that both plungers are equal levels or there is no pressure due to elevation head. So we are only dealing with static pressure exerted by the hydraulic oil on both plungers to be equal. This part is an application of Pascal's Law:

Pi = Po

Fi / Ai = Fo / Ao

Fi = Ai / Ao * Fo

Fi = (ri/ro)^2 * Fo

Fi = ( 0.00861 / 0.141 )^2 * 23000

Fi = 85.76 N

For part b.

- We see that both plungers are at different levels so there is pressure due to elevation head. So we are only dealing with static pressure exerted by the hydraulic oil on both plungers plus the differential in heads. This part is an application of Bernoulli's Equation:

Pi = Po + ρ*g*h

Where, h = Elevation head = 1.10m

Fi = (ri/ro)^2 * Fo + ρ*g*h*π*ri^2

Fi = 85.76 + (804*9.81*1.1*3.142*0.00861^2)

Fi = 87.8 N

3 0

2 years ago

Which of one of Newtons laws are being tested here? Explain how this law relates to figure one

Bess [88]

Answer:

Newtons second law (f=m×a)

Explanation:

The mount of force put into the straw or onto the balloon impacts the acceleratoion and is effected by the mass.

7 0

2 years ago