Question

A projectile fired up into the air at an angle has a range of 235 m and a flight time of 47 s.

Answer 1

Answer:5$ms^{-1}$,133.6$m$,51.18$ms^{-1}$

Explanation:

Let $v_{x}$,$v_{y}$ be the horizontal and vertical components of velocity.

Question a:

Horizontal component of velocity is the ratio of range and time of flight.

So,horizontal component of velocity is $\frac{235}{47}=5ms^{-1}$

So,$v_{x}=5ms^{-1}$

Question b:

Time of flight=$\frac{2v_{y}}{g}$

So,$v_{y}=\frac{47\times 9.8}{2}=51.18ms^{-1}$

Maximum height is given by $\frac{v_{y}^{2}}{2g}$

So,maximum height is $\frac{51.18^{2}}{2\times 9.8}=133.6m$

Question c:

The vertical velocity is already calculated in Question b.

$v_{y}=51.18ms^{-1}$