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3 years ago

Is a decrease in velocity considered an acceleration

Physics

1 answer:

Dovator [93]3 years ago

5 0

Yes an change in velocity either a decrease or increase is an acceleration.

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How much heat is needed to boil 5.30 kg of water at its boiling point?

vivado [14]

Answer:

Required heat Q = 11,978 KJ

Explanation:

Given:

Mass = 5.3 kg

Latent heat of vaporization of water = 2,260 KJ / KG

Find:

Required heat Q

Computation:

Required heat Q = Mass x Latent heat of vaporization of water

Required heat Q = 5.3 x 2260

Required heat Q = 11,978 KJ

Required heat Q = 12,000 KJ (Approx.)

4 0

3 years ago

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Which fossil fuel creates the least amount of pollution when it’s burned ?

love history [14]

Natural gas creates the least amount of pollution when it's burned

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4 years ago

A 3.50-meter length of wire with a cross-sectional area of 3.14 × 10-6 meter2 is at 20° Celsius. If the wire has a resistance of

maks197457 [2]

Answer:

$5.6\times 10^{-8}\ Ohm.m$

Explanation:

Resistivity is given by $\rho=\frac {AR}{L}$ where A is cross-sectional area, R is resistance, L is the length and $\rho$ is the reistivity. Substituting 0.0625 for R, 3.14 × 10-6 for A and 3.5 m for L then the resistivity is equivalent to

$\rho=\frac {3.14\times 10^{-6}\times 0.0625}{3.5}=5.60714285714285714285714285714285714285\times 10^{-8}\approx 5.6\times 10^{-8}\ Ohm.m$

8 0

3 years ago

What is the mass in grams of 5.50 × 1014 lead (pb) atoms?

olchik [2.2K]

There will be no way that to happen aton is a positive charge

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3 years ago

A 110 kg football player running with a velocity of 5.0 m/s hits another stationary football

KengaRu [80]

Answer:

The final velocity of the second player is 6.1 m/s.

Explanation:

The final velocity of the second player can be calculated by conservation of linear momentum (p):

$p_{i} = p_{f}$

$m_{a}v_{a_{i}} + m_{b}v_{b_{i}} = m_{a}v_{a_{f}} + m_{b}v_{b_{f}}$ (1)

Where:

$m_{a}$ : is the mass of the first football player = 110 kg

$m_{b}$ : is the mass of the second football player = 90 kg

$v_{a_{i}}$ : is the initial velocity of the first football player = 5.0 m/s

$v_{b_{i}}$ : is the initial velocity of the second football player = 0 (he is at rest)

$v_{a_{f}}$ : is the final velocity of the first football player = 0 (he stops after the impact)

$v_{b_{f}}$ : is the final velocity of the second football player =?

By solving equation (1) for $v_{b_{f}}$ we have:

$110 kg*5.0 m/s + 0 = 0 + 90 kg*v_{b_{f}}$

$v_{b_{f}} = \frac{110 kg*5.0 m/s}{90 kg} = 6.1 m/s$

Therefore, the final velocity of the second player is 6.1 m/s.

I hope it helps you!

8 0

3 years ago