Is ‘velocity’the displacement of an object during specific unit of time?
2 answers:
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Answer:
velocity = 472 m/s
velocity = 52.4 m/s
Explanation:
given data
steady rate = 0.750 m³/s
diameter = 4.50 cm
solution
we use here flow rate formula that is
flow rate = Area × velocity .............1
0.750 = × (4.50×
)² × velocity
solve it we get
velocity = 472 m/s
and
when it 3 time diameter
put valuer in equation 1
0.750 = × 3 × (4.50×
)² × velocity
velocity = 52.4 m/s
Answer:
v = 7.67 m/s
Explanation:
Given data:
horizontal distance 11.98 m
Acceleration due to gravity 9.8 m/s^2
Assuming initial velocity is zero
we know that
solving for t
we have
substituing all value for time t
t = 1.56 s
we know that speed is given as
v = 7.67 m/s
Answer:
a)188.65m
b)154.35m
c)243.7m
Explanation:
Given data:
(a) The distance from the kicker to each of the 2 spectators is given by:
where,
v= speed of sound
=time taken for the sound waves to reach the ears
m
(b)
where,
v= speed of sound
=time taken for the sound waves to reach the ears
(c)As the angle b/w slight lines from the two spectators to the player is right angle,
hypotenuse=the distance b/w 2 spectators
and, the slight lines are the other 2 lines