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3 years ago

Wel.

Physics

1 answer:

Law Incorporation [45]3 years ago

4 0

Answer:

1 is c 2 is a and 3 is b hope that helped!

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What is located between the galaxies

nekit [7.7K]

Hey there,
The answer is voids, it is probably nearly empty.

Hope this helps :))

~Top

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3 years ago

*brainlest* An object accelerates from rest with a constant acceleration of 2m/s^2. How far will it have moved after 9s? Equatio

boyakko [2]

Answer: You throw an object upwards from the ground with a velocity of 20m/s and it is subject to a downward

acceleration of 9.8 m/s2. How high does it go?

Given Formula Set up Solution

vi=20 m/s

vf=0 m/s

a=-9.8 m/s2

x=?

2 = vi

2 + 2a x (0 m/s)2= (20 m/s)2 + 2 (-

9.8 m/s2) x

x=20.4 meters

Explanation: i known/ i hoped that helped.

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3 years ago

State the Newton's second law of motion

Llana [10]

Answer:

It states that the time rate of change of the momentum of a body is equal in both magnitude and direction to the force imposed on it. ... The momentum of a body is equal to the product of its mass and its velocity.

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2 years ago

Read 2 more answers

For a huge luxury liner to move with constant velocity, its engines need to supply a forward thrust of 7.45 105 N. What is the m

ehidna [41]

Answer:

Explanation:

according to newtons second law of motion;

$\sum F_x = ma_x\\F_{app} - F_r = ma_x$

Fapp is the applied force

Fr is the resistive force

m is the mass of the luxury

a is the acceleration

Since the huge luxury liner move with constant velocity, then acceleration is zero i.e a = 0. The equation becomes;

$F_{app} - F_f = m(0)\\F_{app} - F_f =0\\F_{app} = F_f$

This shows that the applied force will be equal to the resistive force if the velocity is constant.

Given Fr = 7.45 10^5 N therefore the resistive force will also be 7.45 10^5N.

<em>Hence the magnitude of the resistive force exerted by the water on the cruise ship is 7.45 10^5N.</em>

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3 years ago

Which object has the greatest amount of kinetic energy?

EleoNora [17]

I think that the answer is A

4 0

3 years ago