When the material that exits is lesser in amount than that of the entering material in a black box experiment, the parts of the system need to be changed.
<h3>What happens in a black box experiment?</h3>
In a black box experiment, the experimenters need to make assumptions regarding the drawing of conclusions. One such conclusion is the amount of material that exits.
If such amount is lesser than the one that enters the system, such experiment concludes that it is the time to change the parts of the system.
Hence, option D holds true regarding the black box experiment.
Learn more about black box experiment here:
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I think it’s B.) it’s signed by the customer
Answer:
(1). False, (2). True, (3). False, (4). False, (5). True.
Explanation:
The term ''contouring'' in this question does not have to do with makeup but it has to deal with the measurement of all surfaces in planes. It is a measurement in which the rough and the contours are being measured. So, let us check each questions again.
(1). In contouring, it is necessary to measure position and not velocity for feedback.
ANSWER : b =>False. IT IS NECESSARY TO MEASURE BOTH FOR FEEDBACK.
(2). In contouring during 2-axis NC machining, the two axes are moved at the same speed to achieve the desired contour.
ANSWER: a=> True.
(3). Job shop is another term for process layout.
ANSWER: b => False
JOB SHOP IS A FLEXIBLE PROCESS THAT IS BEING USED during manufacturing process and are meant for job Production. PROCESS LAYOUT is used in increasing Efficiency.
(4). Airplanes are normally produced using group technology or cellular layout.
ANSWER: b => False.
(5). In manufacturing, value-creating time is greater than takt time.
ANSWER: a => True.
Answer:
the maximum height h to which the the water steam could rise is 40.65m
Explanation:
Given;
= 20m,
= 2atm ≈ 20265 N/m
Density of water ρ = 1000 kg/
Note: we take point 1 at the free surface of the water in the tank and point 2 at the top of the water trajectory. we also take reference level at the bottom of the tank.
fluid velocity at the free surface of tank is very low (
≅ 0) and at the top of the water trajectory 
= 0
Step 1: Applying Bernoulli equation between poin 1 and point 2
/ρg + 
/2g + = 
/ρg + 
/2g + 
/ρg + = 
/ρg +
= ( - )/ρg +
Substituting values into we have,
= 
Because of the skin depth effect, the current at high frequency tends to flow at very low depth from radius. Then at high frequency the effective cross section of the wire is narrower than at DC.
Fro example skin depth at 100 kHz is 0.206 mm (0.008”), a wire more thicker than AWG26 could be a waste of copper, better use a bunch of thin wire (Litz wire) to rise the Q factor.
