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3 years ago

Where do surface waves occur

1 answer:

6 0

In physics, a surface wave can occur along any boundary of two different substances. The seismic type of surface wave happens at the boundary between air and rock—the surface of the earth.

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You might be interested in

How many atoms are in 57.5 liters of xenon gas at STP

TiliK225 [7]

Answer:

1.55 × 10²⁴ atoms Xe

General Formulas and Concepts:

Atomic Structure

Reading a Periodic Table
Moles
STP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 K
Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Stoichiometry

Using Dimensional Analysis

Explanation:

Step 1: Define

[Given] 57.5 L Xe at STP

[Solve] atoms Xe

Step 2: Identify Conversions

[STP] 22.4 L = 1 mol

Avogadro's Number

Step 3: Convert

[DA] Set up: $\displaystyle 57.5 \ L \ Xe(\frac{1 \ mol \ Xe}{22.4 \ L \ Xe})(\frac{6.022 \cdot 10^{23} \ atoms \ Xe}{1 \ mol \ Xe})$
[DA] Divide/Multiply [Cancel out units]: $\displaystyle 1.54583 \cdot 10^{24} \ atoms \ Xe$

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

1.54583 × 10²⁴ atoms Xe ≈ 1.55 × 10²⁴ atoms Xe

4 0

3 years ago

Which technology is shown in the photograph?

jekas [21]

Answer:

Explanation:

Apex

7 0

3 years ago

If you go into the lab and dissolve 2.11 g of magnesium chloride in enough water to make 1500 ml of solution, what is the molari

dusya [7]

Moles pf mgcl2= 2,11/M mgcl2=2,11/95= 0,0222

Molarity=0,0222/1,5=0,0148 M.

I hope this is correct.

4 0

3 years ago

Given what you observe at the molecular/atomic level, why would surface area have this effect?

LenKa [72]

Answer:

Increasing the surface area of a reactant increases the frequency of collisions and increases the reaction rate. Several smaller particles have more surface area than one large particle. The more surface area that is available for particles to collide, the faster the reaction will occur.

Explanation:

5 0

2 years ago

defon

1) Calcium carbonate contains 40.0% calcium by weight.
M(CaCO₃)=100.1 g/mol
M(Ca)=40.1 g/mol
w(Ca)=40.1/100.1=0.400 (40.0%)!

2) Mass fraction of this is excessive data.

3) The solution is:

m(Ca)=1.2 g

m(CaCO₃)=M(CaCO₃)*m(Ca)/M(Ca)

m(CaCO₃)=100.1g/mol*1.2g/40.1g/mol=3.0 g

4 0

3 years ago

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