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BARSIC [14]
3 years ago
15

Uranium has atomic number 92. Its most common isotope is 238U, but the form used in nuclear bombs and nuclear power plants is 23

5U. How many neutrons are in each of these two isotopes of uranium
Chemistry
1 answer:
Yakvenalex [24]3 years ago
3 0

Explanation:

Atomic Number = Number of protons

Mass Number = Number of protons + Number of neutrons

Isotopes are simply atoms of an element with the same number of protons and different number of neutrons.

First Isotope -- 238U

Number of neutrons = Mass Number - Atomic Number

Number of neutrons =  238 - 92 = 146

Second Isotope -- 235U

Number of neutrons = Mass Number - Atomic Number

Number of neutrons =  235 - 92 = 143

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bazaltina [42]

Answer:

-3.15 °Celsius I think.

8 0
3 years ago
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A glucose solution is administered intravenously into the bloodstream at a constant rate r. As the glucose is added, it is conve
Helen [10]

Answer:

C(t)=\frac{r}{k}-(\frac{r-kC_o}{k})e^{-kt}

Explanation:

The differential equation is given as:

\frac{dC}{dt} = r- kC

\frac{dC}{r- kC} = dt

Taking integral of both sides; we have:

\int\limits  \frac{dC}{r- kC} = \int\limits dt

-\frac{1}{k} In(r-kC) = t+D\\In(r-kC)=-kt-kD

r-kC=e^{-kt-kD}

r-kC=e^{-kt}e^{-kD}

r-kC=Ae^{-kt}

kC=r-Ae^{-kt}

C=\frac{r}{k}-\frac{A}{k}e^{-kt}

C(t)=\frac{r}{k}-\frac{A}{k}e^{-kt}     ------- equation (1)

If C(0)= C_o ; we have:

C(0)= \frac{r}{k}-\frac{A}{k}e^0         (where; A is an integration constant)

C_o = \frac{r}{k}- \frac{A}{k}

C_o=\frac{r-A}{k}

kC_o=r-A

A=r-kC_o

Substituting A=r-kC_o into equation (1); we have;

C(t)=\frac{r}{k}-(\frac{r-kC_o}{k})e^{-kt}

3 0
4 years ago
To what volume (in milliliters) should you dilute 100.0 mL of a 5.50 M solution of CaCl2 solution to obtain a 0.950 M solution o
Alexxx [7]

Dilution law is given as:

M_{1}V_{1}=M_{2}V_{2}    (1)

where, M_{1} = molarity of initial concentrated solution.

V_{1} = volume of initial concentrated solution.

M_{2} = molarity of final diluted solution.

tex]V_{2}[/tex] = volume of final diluted solution.

Volume of initial concentrated solution of CaCl_{2}= 100.0 mL

Molarity of initial concentrated solution of CaCl_{2}= 5.50 M

Volume of final diluted solution of CaCl_{2} = 0.950 M

Put the values in formula (1),

5.50 M\times 100.0 mL=0.950 M\times V_{2}

V_{2} =\frac{5.50 M\times 100.0 mL}{0.950 M}

V_{2} =578.9 mL

Hence, final diluted volume of the solution is  578.9 mL.





3 0
4 years ago
The empirical formula for a compound is C2H4NO. If its molar mass is 232.2 g/mol, what is the molecular formula of the compound?
Irina18 [472]

Empirical formula mass

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Molar mass=232.2g/mol

Find n

  • Molar mass/Empirical formula mass
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Molecular formula

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4 0
2 years ago
The chemical equation below shows the reaction between carbon dioxide (CO2) and lithium hydroxide (LiOH). CO2 + 2LiOH mc011-1.jp
Sunny_sXe [5.5K]
From the given balanced chemical equation,
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we can conclude that for every 2 moles of LiOH, we need a mole of CO2. Calculate first the number of moles of CO2 by dividing the given mass by the molar mass giving us an answer of 0.58 moles. Using proportionality,
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The value of x is equal to 1.16 moles. 
5 0
3 years ago
Read 2 more answers
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