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3 years ago

How do you perform calculations relating to isotopes. describe please

Chemistry

1 answer:

Zigmanuir [339]3 years ago

8 0

Explanation:

I'm not sure if this is what you are looking for but i will attempt to answer.

Isotopes are variations of the same atom. They have the same number of protons but have a different number of neutrons. As a result of this, the atomic number remains the same but the mass number changes.

A calculation you could perform in relation to isotopes would be calculating the relative atomic mass. The relative atomic mass is the weighted average of masses of isotopes.

Relative atomic mass (RAM)= the addition of

$\frac{relative \: isotopic \: mass \times percentage \: abundance}{100 }$

For example, the element Indium has a relative isotopic mass of 112.90406, 4.29% of the time. It has a relative isotopic mass of 114.903878, 95.71% of the time.

From this

RAM=

$\frac{112.904061 \times 4.29}{100} + \frac{114.903878 \times 95.71}{100} = 114.8(4 \: sig \: figs)$

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2 years ago

Bath salts are typically composed of the ingredients listed below. Identify each item as being acidic, basic, or neutral when di

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Answer:

NaCl neutral

Na₂SO₄ basic

NaHCO₃ basic

K₃PO₄ basic

Na₃C₆H₅O₇ basic

CaCl₂ neutral

Sodium oxalate (Na₂C₂O₄) dissolves and dissociates in water.

Oxalic acid (C₂H₂O₄) dissolves and dissociates in water

Explanation:

<em>Identify each item as being acidic, basic, or neutral when dissolved in water. If a particular ingredient does make an acidic or basic solution, describe how this occurs.</em>

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NaCl

When NaCl is dissolved in water the resulting solution is neutral.

Na₂SO₄

When Na₂SO₄ is dissolved in water the resulting solution is basic due to the basic hydrolysis of the SO₄²⁻ ion.

SO₄²⁻(aq) + H₂O(l) ⇄ HSO₄⁻(aq) + OH⁻(aq)

NaHCO₃

When NaHCO₃ is dissolved in water the resulting solution is basic due to the basic hydrolysis of the HCO₃⁻ ion.

HCO₃⁻(aq) + H₂O(l) ⇄ H₂CO₃(aq) + OH⁻(aq)

K₃PO₄

When K₃PO₄ is dissolved in water the resulting solution is basic due to the basic hydrolysis of the PO₄³⁻ ion.

PO₄³⁻(aq) + H₂O(l) ⇄ HPO₄²⁻(aq) + OH⁻(aq)

Na₃C₆H₅O₇ (sodium citrate)

When Na₃C₆H₅O₇ is dissolved in water the resulting solution is basic due to the basic hydrolysis of the C₆H₅O₇³⁻ ion.

C₆H₅O₇³⁻(aq) + H₂O(l) ⇄ C₆H₆O₇²⁻(aq) + OH⁻(aq)

CaCl₂

When CaCl₂ is dissolved in water the resulting solution is neutral.

Sodium oxalate (Na₂C₂O₄) dissolves and dissociates in water according to the following equation:

Na₂C₂O₄(aq) ⇄ 2 Na⁺(aq) + C₂O₄²⁻(aq)

Oxalic acid (C₂H₂O₄) dissolves and dissociates in water according to the following equation:

C₂H₂O₄(aq) ⇄ C₂HO₄⁻(aq) + H⁺(aq)

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