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astraxan [27]
3 years ago
7

How do you perform calculations relating to isotopes. describe please

Chemistry
1 answer:
Zigmanuir [339]3 years ago
8 0

Explanation:

I'm not sure if this is what you are looking for but i will attempt to answer.

Isotopes are variations of the same atom. They have the same number of protons but have a different number of neutrons. As a result of this, the atomic number remains the same but the mass number changes.

A calculation you could perform in relation to isotopes would be calculating the relative atomic mass. The relative atomic mass is the weighted average of masses of isotopes.

Relative atomic mass (RAM)= the addition of

\frac{relative \: isotopic \: mass \times percentage \: abundance}{100 }

For example, the element Indium has a relative isotopic mass of 112.90406, 4.29% of the time. It has a relative isotopic mass of 114.903878, 95.71% of the time.

From this

RAM=

\frac{112.904061 \times 4.29}{100}  +  \frac{114.903878 \times 95.71}{100}  = 114.8(4 \: sig \: figs)

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How many moles of MgO are produced when .250 mol of Mg reacts completely with O2
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Answer:

0.250 moles of MgO are produced when 0.250 mol of Mg reacts completely with O₂

Explanation:

In first place, the balanced reaction between Mg and O₂ is:

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By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of reactants and products participate in the reaction:

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Then you can apply the following rule of three: if by reaction stoichiometry 2 moles of Mg produce 2 moles of MgO, 0.250 moles of Mg, how many moles of MgO will they form?

moles of MgO=\frac{0.250 moles of Mg*2 moles of MgO}{2 moles of Mg}

moles of MgO= 0.250

<u><em>0.250 moles of MgO are produced when 0.250 mol of Mg reacts completely with O₂</em></u>

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