Question

The product of two consecutive even integers is 10 less than 5 times their sum. Find two integers

Answer 1

Let one of the numbers be x
The other number is x + 2

x(x + 2) = 5( x + x + 2) - 10
x² + 2x = 10x + 10 - 10
x² - 8x = 0
x(x - 8) = 0
x = 0 or x = 8

x = 8,
x + 2 = 10

Answer: The numbers are 8 and 10.

Answer 2

X(x+2)=5(x+x+2)-10
x^2+2x=10x+10-10
x^2-8x=0
x(x-8)
 The answer is 0 and/or 8.