Answer:
Please find the complete solution in attached file.
Explanation:
To determine the temperature of the gas, we need to assume ideal gas to use the equation PV=nRT where P represents the pressure, V is the volume, n is the number of moles, T is the temperature and R is the universal gas constant. We calculate as follows:
PV = nRT
T = PV / nR
T = (1.26 atm) ( 208 L ) / 0.08205 L-atm/mol-K ( 9.95 mol )
T = 321.02 K
Hope this answers the question.
Answer:
561 g P₂O₃
Explanation:
To find the mass of P₂O₃, you need to (1) convert moles H₃PO₃ to moles P₂O₃ (via mole-to-mole ratio from equation coefficients) and then (2) convert moles P₂O₃ to grams P₂O₃ (via molar mass). It is important to arrange the ratios/conversions in a way that allows for the cancellation of units. The final answer should have 3 sig figs to match the amount of sig figs in the given value.
Atomic Mass (P): 30.974 g/mol
Atomic Mass (O): 15.998 g/mol
Molar Mass (P₂O₃): 2(30.974 g/mol) + 3(15.998 g/mol)
Molar Mass (P₂O₃): 109.942 g/mol
1 P₂O₃ + 3 H₂O -----> 2 H₃PO₃
10.2 moles H₃PO₃ 1 mole P₂O₃ 109.942 g
---------------------------- x -------------------------- x ------------------- = 561 g P₂O₃
2 moles H₃PO₃ 1 mole
The answer is A there i 1 atom