The alkaline earth metals (the second group) because their ion charge is +2
Answer:
Explanation:
Reaction given
6 H⁺ + 2 MnO₄⁻ + 5 (COOH)₂ = 10CO₂ +8H₂O + 2 Mn⁺²
Oxidation number of Mn in MnO₄⁻
= x - 4 x 2 = -1
x = 8 -1
+ 7
Oxidation no of Mn in Mn⁺² = +2
So its oxidation no is decreased from + 7 to + 2 . Hence it is reduced.
Trisulfur nonaiodide
Step-by-step explanation:
The name for a binary molecular compound has the form
Multiplying prefix+name of first element multiplying prefix+stem of second element element+ide (two words)
The multiplying prefixes for three and nine are tri and nona, respectively.
The stem of iodine is iod.
Put them together, and the name of S₃I₉ is
trisulfur nonaiodide.
The answer to this is B, solids with a repeating atomic pattern.
Convert 0.47g 2-naphthol to mols. mol = g/molar mass.
Using the coefficients in the balanced equation, convert mols 2-naphthol to mols 2-butoxynaphthalene then you have to Convert mol 2-butoxynaphthalene to grams. g = mols x molar mass. This is the theoretical yield.
