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Gala2k [10]
3 years ago
8

HELP A car traveling at 4m/s accelerates at a rate of .80m/s2 for 1.8s. What is its final velocity?

Physics
2 answers:
Semenov [28]3 years ago
4 0

Answer:

148(m/s)

Explanation:

V_final = V_current + (acceleration) x (time)

            = 4 + 80 x 1.8 = 148 (m/s)

vlabodo [156]3 years ago
3 0
ANSWER:
Given:
u(initial velocity)=4m/s
a(acceleration)=80m/s^2
t(time)=1.8seconds
To find final velocity denoted by v-
We will use first derivation of motion.
v=u+at
v=4+(80)(1.8)
v=4+144
v=148m/s^-1 or 144m/s
HOPE IT HELPS!!!!!!
PLEASE MARK BRAINLIEST!!!!!
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Answer:pounds

Explanation:

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2 years ago
An open pipe of length 0.39m vibrates in the third harmonic with a frequency of 1400Hz. What is the distance from the center of
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Length of the pipe = 0.39 m

Third harmonic frequency = 1400 Hz

For the third harmonic:

Wavelength = \frac{2L}{3}

The center of the open pipe will host a node and the nearest anti - node from the center will be at the 0.25 × wavelength

Distance from center  = 0.25 × wavelength

Distance = 0.25 x \frac{2L}{3}

Plugging the value of the length of the pipe (L) = 0.39 m = 39 cm

Distance = 0.25 x \frac{2 \times 39}{3}

Distance from the center to the nearest anti - node = 6.5 cm

Hence, the nearest distance to the anti - node from the center = 6.5 cm

So, option C is correct.

7 0
3 years ago
A woman pushes an oak chest across an oak floor at a constant speed of 0.450 m/s. The chest has a mass of 40.0 kg, and the coeff
natima [27]

Answer:

A. 243 N

Explanation:

Friction is the force that opposes the relative motion between systems that are in contact.

This friction force that opposes the motion of the oak chest across the oak surface will be equal and opposite to that exerted by the woman.

First find the normal force which is the force that would point directly upwards to support weight of the block.

Normal force, N= mg where m is the mass of the chest and g is the acceleration due to gravity.

Given m=40 kg and g=9.80 m/s²

N force=40×9.80 =392N

Then find the force of friction which is given by the formula;

<em>F=μN where μ is friction coefficient for the  oak chest  and N is the normal force on the chest</em>

Given <em>μ</em>=0.620  and N force = 392 N then it will be;

F=0.620× 392 =243.04 N

Answer : 243 N

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An object has a weight of 9 n when it is in air and 7.2 n when it is submerged into water. what is the specific gravity of the o
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The specific gravity of the object’s material is 5.09.

<h3>To calculate the specific gravity of the object:</h3>

Weight difference = 9 - 7.2 = 1.8 N = Buoyant force of water

Buoyant Force in water(Fb) = density of water x g x volume of the   body(Vb)

1.8 = 1000 x 9.81 x Vb

Vb = 1.8/9810 cubic meter

Now, in the air;

Weight of body = mg = 9 N

Mass of body,m = 9/9.81 Kg

So,

Density of body = m/ Vb

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Therefore, Specific gravity of body = 5.09

Learn more about Specific gravity here:

brainly.com/question/13258933

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6 0
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