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julsineya [31]
3 years ago
8

Why does the emission of an alpha particle always result in transmutation?

Physics
1 answer:
prohojiy [21]3 years ago
4 0

Explanation:

some radioactive isotope are present as terrestrial radiation other radioactive isotope are produced by humans via nuclear reactions which is result in unstable combination of neutrons and proton one way of artificially inducing nuclear transmutation is by bombarding stable isotopes with alpha particles

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An organ pipe open at both ends has two successive harmonics with frequencies of 220 Hz and 240 Hz. What is the length of the pi
Harman [31]

Answer:

The  length is  l  =  8.6 \  m

Explanation:

From the question we are told that

   The frequencies of the two successive harmonics are f_1 =  220 \ Hz ,  f_2  =  240 \  Hz

   The speed of sound in the air is  v_s  =  343 \  m/s

Generally the frequency of a given harmonic is mathematically represented as

     f_n  =  \frac{n  v  }{2l}

Here  n defines  the position of the harmonics

Now since the position of both harmonic is not know but we know that they successive then we can represented them mathematically as

    220  =  \frac{n v}{2l}

and  

     240  =  \frac{(n+1) v}{2l}

So

   \frac{(n + 1 ) v}{2l} - \frac{n v}{2l}  =  240-220

=>  \frac{v}{2l}  =  20

=>   l  =  8.6 \  m

7 0
3 years ago
Let’s say I am in a bumper car and have a velocity of 14 m/s, driving in the positive x-direction. I and my bumped car have a ma
AlekseyPX

Answer:

160 kg

12 m/s

Explanation:

m_1 = Mass of first car = 120 kg

m_2 = Mass of second car

u_1 = Initial Velocity of first car = 14 m/s

u_2 = Initial Velocity of second car = 0 m/s

v_1 = Final Velocity of first car = -2 m/s

v_2 = Final Velocity of second car

For perfectly elastic collision

m_{1}u_{1}+m_{2}u_{2}=m_{1}v_{1}+m_{2}v_{2}\\\Rightarrow m_2v_2=m_{1}u_{1}+m_{2}u_{2}-m_{1}v_{1}\\\Rightarrow m_2v_2=120\times 14+m_2\times 0-(120\times -2)\\\Rightarrow m_2v_2=1920\\\Rightarrow m_2=\frac{1920}{v_2}

Applying in the next equation

v_2=\frac{2m_1}{m_1+m_2}u_{1}+\frac{m_2-m_1}{m_1+m_2}u_2\\\Rightarrow v_2=\frac{2\times 120}{120+\frac{1920}{v_2}}\times 14+\frac{m_2-m_1}{m_1+m_2}\times 0\\\Rightarrow \left(120+\frac{1920}{v_2}\right)v_2=3360\\\Rightarrow 120v_2+1920=3360\\\Rightarrow v_2=\frac{3360-1920}{120}\\\Rightarrow v_2=12\ m/s

m_2=\frac{1920}{v_2}\\\Rightarrow m_2=\frac{1920}{12}\\\Rightarrow m_2=160\ kg

Mass of second car = 160 kg

Velocity of second car = 12 m/s

5 0
4 years ago
What is the cause of most waves and how can this change waves' characteristics?
Tanzania [10]

There are three main factors that affect wave formation: wind velocity, fetch, and duration.

Waves are most commonly caused by wind. Wind-driven waves, or surface waves, are created by the friction between wind and surface water. As wind blows across the surface of the ocean or a lake, the continual disturbance creates a wave crest.

8 0
3 years ago
Read 2 more answers
A student redid the experiment of mixing room temperature water and warm
Len [333]

Answer:

I think B or C it won't lower so I'll go with B bc warm water is hotter than regular temp water

7 0
3 years ago
Read 2 more answers
A sled is pulled with a horizontal force of 18 n along a level trail, and the acceleration is found to be 0.39 m/s2. an extra ma
Natali5045456 [20]
From Newton's second law of motion, it is identified that the net force applied to the object with mass m, will make it move with an acceleration of a. This can be mathematically translated as,
                        F = m x a
To solve for the mass of the sled, we derive the equation above such that,
                        m = F / a
Substituting,
                       m = (18 N) / (0.39 m/s²)
                          m = 46.15 kg

Then, we add to the calculated mass the mass of the extra material.
                      total mass = 46.15kg + 4.5 kg
                       total mass = 50.65 kg
We solve for the normal force of the surface to the object by calculating its weight.
                     F₂ = (50.65 kg)(9.8 m/s²)
                     F₂ = 496.41 N

The force that would allow barely a movement for the object is equal to the product of the normal force and the coefficient of kinetic friction.
                     F = (F₂)(c)
                      c = F/F₂

Substituting,
                      c = 18 N/496.41 N
                       c = 0.0362

<em>ANSWER: c = 0.0362</em>

5 0
3 years ago
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