Answer:
600.7 moles
Explanation:
Applying,
PV = nRT................... Equation 1
Where P = Pressure of oxygen, V = Volume of oxygen, n = number of moles, R = molar gas constant, T = Temperature.
make n the subject of the equation
n = PV/RT............... Equation 2
From the question,
Given: P = 190 atm, V = 35 L, T = 135 K
Constant: R = 0.082 atm.dm³/K.mol
Substitute these values into equation 2
n = (190×35)/(135×0.082)
n = 600.7 moles of xygen
Answer: 0.18 M
Explanation:
Initial molarity, M1 = 0.8 M
Initial olume, V1 = 225 ml
Final volume, V2 = 1000 ml
Final Molarity, M2 = M1V1/V2
= 0.8 x 225/1000
= 0.18 M
Answer:
Force of attraction = 35.96
N
Explanation:
Given: charge on anion = -2
Charge on cation = +2
Distance = 1 nm =
m
To calculate: Force of attraction.
Solution: The force of attraction is calculated by using equation,
---(1)
where, q represents the charge and the subscripts 1 and 2 represents cation and anion.
k = 
F = force of attraction
r = distance between ions.
Substituting all the values in the equation (1) the equation becomes

Force of attraction = 35.96
N
Answer:
b) 5.87 E23 molecules
Explanation:
∴ mm SO3 = 80.066 g/mol
⇒ molecules SO3 = (78.0 g)(mol/80.066 g)(6.022 E23 molec/mol)
⇒ molec SO3 = 5.866 E23 molecules SO3
Molal or molar? There is a difference