By using Displacement method we can find volume of irregular object like marble.
<h3>What is
displacement method?</h3>
In displacement method,
First , we measuring the volume of water displaced by an object which tell us the volume of the object.
Secondly We can use the physical balance to determine its mass.
Lastly , calculate the density by dividing the mass by the volume.
Procedure to find the Volume of irregular object i.e. marble
step 1 - Fill the graduated cylinder about half full and measure the initial volume of water.
step 2 - Drop the marble in the graduated cylinder.
step 3 -Now measure the final level of water.
Step 4 - Subtract both the values.
Here , comes the Volume of Irregular Object.
For more volume related question visit here:
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Answer:
No there is no displacement observed so no work done
I used to play tag or run around a lot and sometimes i do these activities but its a lot less now that i am older
Answer:
(a) the time needs for her to cross the river is 2736.8 s.
(b) the distance takes to reach the other side of the river is 2490.5 m.
Explanation:
given information:
woman's speed, v₁ = 1.9 m/s
the wide of river, s = 5.2 km = 5200 m
river's current, v₂ = 0.91 m/s
(a) How much time does it take her to cross the river?
s = v t
s = the displacement (m)
v = speed (m/s)
t = time (s)
s = v t
t = s/v
= 5200/1.9
= 2736.8 s
(b) How far downstream will the river carry her by the time she reaches the other side of the river?
s = v t
= (0.91) (2736.8)
= 2490.5 m
Answer:

Explanation:
<u>Displacement</u>
It is a vector that points to the final point where an object traveled from its starting point. If the object traveled to several points, then the individual displacements must be added as vectors.
The mail carrier leaves the post office and drives 2 km due north. The first displacement vector is

Then the carrier drives 7 km in 60° south of east. The displacement has two components in the x and y axis given by

Finally, he drives 9.5 km 35° north of east.

The total displacement is


The direction can be calculated with

