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lisabon 2012 [21]

3 years ago

11

What were the physical activities in your childhood that you still do today? Do you spend more time now in doing these activitie

s as compared before?

1 answer:

user100 [1]3 years ago

5 0

I used to play tag or run around a lot and sometimes i do these activities but its a lot less now that i am older

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Calculate the heat energy needed to change the temperature of 2 kg of copper from 10°C to 110°C.

serious [3.7K]

<span>The specific heat (or the amount of heat required to raise the temperature of a unit mass of a substance by 1 degree Celsius) of copper is about 0.386 J/g/degree Celsius. This means that if we supply 0.386 J of energy to 1 gram of copper, its temperature will increase by 1 degree Celsius.</span>

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3 years ago

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It's five miles from Tim's house to Rita's house. Roughly how long is this distance in feet?

sergey [27]

Answer:

26400 ft

Explanation:

that would be my answer

hope this helps!!! :)

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3 years ago

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Which produces more gravitational force on your textbook: you or the earth?

Yuri [45]

The earth obviously because it is on Earth like we are and it has the same gravital properties. It falls when you drop it and rises when you pick it up

5 0

3 years ago

If you are following a car and also being tailgated by another vehicle, your best option would be to.. a. Increase the following

Pie

Answer:

Your answer here is D

Explanation:

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7 0

3 years ago

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A horizontal rectangular surface has dimensions 2.80 cm by 3.20 cm and is in a uniform magnetic field that is directed at an ang

koban [17]

Answer:

magnitude of the magnetic field 0.692 T

Explanation:

given data

rectangular dimensions = 2.80 cm by 3.20 cm

angle of 30.0°

produce a flux Ф = 3.10 × $10^{-4}$ Wb

solution

we take here rectangular side a and b as a = 2.80 cm and b = 3.20 cm

and here angle between magnitude field and area will be ∅ = 90 - 30

∅ = 60°

and flux is express as

flux Ф = $\int \vec{B}.d\vec{A}$ .................1

and Ф = BA cos∅ ............2

so B = $\frac{\phi }{Acos\theta }$

and we know

A = ab

so

B = $\frac{\phi }{abcos\theta }$ ..............3

put here value

B = $\frac{3.10\times 10^{-4} }{2.80 \times 10^{-2}\times 3.20 \times 10^{-2}\times cos60}$

solve we get

B = 0.692 T

8 0

3 years ago