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KIM [24]
2 years ago
13

a ball is thrown with an initial velocity of 80 feet per second, at an angle of 40 degrees with the horizontal. Find the vertica

l and horizontal components of the velocity.
Physics
1 answer:
Scorpion4ik [409]2 years ago
7 0
Well velocity is a vector quanity and we can brake vectors in to verticle and horizantal componontes threw these two formulas Vcostheta=Vx and Vsintheta=Vy
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The half-life of iodine-131 is 8.04 days. It’s decay constant equals
Svetllana [295]

Answer:

Explanation:

we know that half life of an element is

T=0.693/λ

where λ is decay constant in order to find decay constant

λ=0.693/T

λ=0.693/8.04

λ=0.086

7 0
2 years ago
What is the gravitational force between a 45 kg person, and the Earth at 5.98 x 1024 kg, with a distance of
Assoli18 [71]

Answer:

C. 441 N

Explanation:

Gravitational force between two objects can by calculated by the formula

= G m₁m₂ / r² , m₁ and m₂ are masses at distance r

= ( 6.67 x 10⁻¹¹ x 45 x 5.98 x 10²⁴) / ( 6.38 x 10⁶ )²

= 44.09 x 10

= 440.9 N

= 441 N .  

7 0
3 years ago
If the jet is moving at a speed of 1300 km/h at the lowest point of the loop, determine the minimum radius of the circle so that
Natalka [10]

Answer:

R = 2216m and The normal force of the seat on the pilot is 5008N

Explanation:

See attachment below please.

5 0
3 years ago
Find the magnitude and direction of a force between a 25.0 coulomb charge and a 40.0coulomb charge when they are separated by a
deff fn [24]

Answer:

95.0 colomb

Explanation:

Make sure to understand the concept

6 0
2 years ago
A capacitor consists of two metal surfaces separated by an insulating layer. A new capacitor has no charge on either of its surf
mihalych1998 [28]
<h2>Answer:</h2><h3>(A) the positively charged surface increases and the energy stored in the capacitor increases.</h3>

When charging a capacitor transferring charge from one surface to the other, the first surface becomes negatively charged while the second surface becomes positively charged. As you transfer the charge, the voltage of the positively charged surface increases and the energy stored in the capacitor also increases. We can solve this by the definition of <em>capacitance</em><em> </em>that is <em>a  measure of the ability of a capacitor  to store energy. </em>For any capacitor, the capacitance is  a constant defined as:

C=\frac{Q}{V_{ab}}

To maintain C constant, if Q increases V also increases.

On the other hand, the potential energy U can be expressed as:

U=\frac{Q^{2}}{2C}

In conclusion, as Q increases the potential energy also increases.

5 0
3 years ago
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