As temperature decreases, the steel will contract (volume decreases) thereby, an increase in Density.
Its b, energy waiting to be used
Answer:
No. of moles, n = 25.022 moles
Given:
Volume of gas in tank, V = 29.1 l
Temperate of gas, T =
= 273 + 35.8 = 308.8 K
Pressure of gas, P = 21.8 atm
Solution:
Making use of the ideal gas equation which given as:
PV = nRT
where
R = Rydberg's constant = 0.0821 L-atm/mol-K
Re-arranging the above formula for 'n' and putting the values in the above formula:

n = 25.022
ind the velocity my using the conservation of energy mgh=1/2mv^2. At the bottom, the mass is turning in a circle with tension pointing up towards the center of the circle and weight pointing down. Use the centripetal force requirement mv^2/r=T-W and solve for T. Hope this helps.
Answer:
705.6 N
Explanation:
The object is hanging on the rope, so there are two forces acting on the object:
- The force of gravity, downward, equal to
W = mg
where m is the mass of the object and g the acceleration of gravity
- The tension in the rope, T, upward
Since the object is hanging motionless, the object is in equilibrium, so we can write:

And therefore

For this problem,
m = 72 kg

Substituting,
