Answer:
The corridor's distance is "90 m".
Explanation:
- She heads in the east directions but creates the first pause, meaning she crosses the distance 'x' in step 1.
- Now, provided that perhaps the distance by her to another fountain or waterfall just after the first stop is twice as far away she traveled.
- Because she moved the distance of 'x,' then, therefore, her distance towards the fountain of '2x.' She casually strolls and once again pauses 60 m beyond her stop.
- The gap about her to the waterfall during that time approximately twice the distance and her to the eastern end of the hallway.
- Assume her gap from either the east end of the platform seems to be 'y' at either the second stop, after which '2y' may become the distance between the 2nd pause and the waterfall.
Now,
⇒ ![2x + 2y = 60](https://tex.z-dn.net/?f=2x%20%2B%202y%20%3D%2060)
⇒ ![x + y = 30](https://tex.z-dn.net/?f=x%20%2B%20y%20%3D%2030)
The total distance of the corridor will be:
= ![x + 2x + 2y + y](https://tex.z-dn.net/?f=x%20%2B%202x%20%2B%202y%20%2B%20y)
= ![3\times (x + y)](https://tex.z-dn.net/?f=3%5Ctimes%20%28x%20%2B%20y%29)
= ![3\times 30](https://tex.z-dn.net/?f=3%5Ctimes%2030)
= ![90 \ m](https://tex.z-dn.net/?f=90%20%5C%20m)
Yes it would get colder because people help people learn through experiences with no one to help teach the world would be a cold lifeless place.
Answer:
u = 10.63 m/s
h = 1.10 m
Explanation:
For Take-off speed ..
by using the standard range equation we have
![R = u² sin2θ/g](https://tex.z-dn.net/?f=R%20%3D%20u%C2%B2%20sin2%CE%B8%2Fg)
R = 9.1 m
θ = 26º,
Initial velocity = u
solving for u
![u² = \frac{Rg}{sin2\theta}](https://tex.z-dn.net/?f=u%C2%B2%20%3D%20%5Cfrac%7BRg%7D%7Bsin2%5Ctheta%7D)
![u^2 = \frac{9.1 x 9.80}{sin26}](https://tex.z-dn.net/?f=u%5E2%20%3D%20%5Cfrac%7B9.1%20x%209.80%7D%7Bsin26%7D)
![u^2 = 113.17](https://tex.z-dn.net/?f=%20u%5E2%20%3D%20113.17)
u = 10.63 m/s
for Max height
using the standard h(max) equation ..
![v^2 = (v_osin\theta)^2 -2gh](https://tex.z-dn.net/?f=v%5E2%20%3D%20%28v_osin%5Ctheta%29%5E2%20-2gh)
![h =\frac{(v_o^2sin\theta)^2}{2g}](https://tex.z-dn.net/?f=h%20%3D%5Cfrac%7B%28v_o%5E2sin%5Ctheta%29%5E2%7D%7B2g%7D)
![h = \frac{(113.17)(sin26)^2}{(2 x 9.80)}}](https://tex.z-dn.net/?f=h%20%20%3D%20%20%5Cfrac%7B%28113.17%29%28sin26%29%5E2%7D%7B%282%20x%209.80%29%7D%7D)
h = 1.10 m
Fuel is produced by fermenting Ethanol
Answer:
Parallel universe, or alternate reality, is a hypothetical self-contained plane of existence, co-existing with one's own