Answer:
The magnitude of the force of friction equals the magnitude of my push
Explanation:
Since the crate moves at a constant speed, there is no net acceleration and thus, my push is balanced by the frictional force on the crate. So, the magnitude of the force of friction equals the magnitude of my push.
Let F = push and f = frictional force and f' = net force
F - f = f' since the crate moves at constant speed, acceleration is zero and thus f' = ma = m (0) = 0
So, F - f = 0
Thus, F = f
So, the magnitude of the force of friction equals the magnitude of my push.
Answer:
8.5 ohms
Explanation:
from ohms law
V=IR
120=14.1R
divide both sides by 14.1
120/14.1=14.1R/14.1
R=8.5ohms
Answer:
Explanation:
When the velocity changes uniformly, the object has a constant acceleration. The acceleration, the velocities, and the distance are related by the equation:
Where:
vf = final velocity
vo = initial velocity
a = acceleration
x = distance
Solving for a:
The car travels a distance of x=200 m and the velocities are:
vo = 216 Km/h
vf = 360 Km/h
Both velocities must be converted to meters by seconds.
vo = 216 Km/h *1000/3600 = 60 m/s
vf = 360 Km/h *1000/3600 = 100 m/s
The acceleration is:
<h2>The work done = - 2 x 10⁴ J</h2>
Explanation:
In the first case , the volume is kept constant and pressure varies .
In isothermal process , the work done
W₁ = V x ΔP
here V is the volume of gas and ΔP is the change in pressure
Thus W₁ = 0
Because there is no change in volume , therefore displacement is zero .
In second case pressure is constant , but volume changes
Thus W₂ = P x ΔV
here P is the pressure and ΔV is the change in volume
Therefore W₂ = 4 x 10⁵ x 5 x 10⁻² = 2 x 10⁴ J
The total work done W = - 2 x 10⁴ J
Because the work done in compression is negative .
I think the answer is 120 minutes hope this helps
