What happens to electron flow with a conductor of the voltage source is removed?

nydimaria [60]

An alpha particle is identical to a helium nucleus ... 2 protons, 2 neutrons. <em>(1)</em>

6 0

3 years ago

una fila di ballerini lunga complessivamente 2,3 m sta avvicinandosi perpendicolarmente a uno specchio. Se il primo ballerino, e

antoniya [11.8K]

Answer:

A Benjamin Franklin

B George Washington

C Abraham Lincoln

D John Adams

7 0

3 years ago

Tell the difference between an internal and an external influence and give 1 examples of each.

Morgarella [4.7K]

Answer:

Si tienen diferencia

Explanation: Internas: Proviene de la herencia; el legado genético que las personas reciben de sus padres.

Externa: Provienen de las experiencias personales frente

al mundo exterior

3 0

3 years ago

A 15.7 kg block is dragged over a rough, horizontal surface by a constant force of 83.1 N

Kay [80]

Answer:

The work done by the 83.1 N force is 4687.5 J.

The magnitude of the work done by the force of friction is 1187.5 J.

Explanation:

Given:

Mass of the block, $m=15.7$ kg

Force acting on it, $F=83.1$ N

Angle of application of force, $\theta = 25.7$ °

Displacement of the block, $d=62.6$ m

Coefficient of friction, $\mu =0.161$

Acceleration due to gravity, $g=9.8$ m/s²

Work done by a force is given as:

$Work,W=F\times d\times \cos\theta$

So, work done by the constant force is given as:

$W_{force}=83.1\times 62.6\times \cos(25.7)\\W_{force}=4687.5\textrm{ J}$

Now, in order to find work done by friction, we need to evaluate friction.

For the vertical direction, the net force is zero as there is no vertical motion.

Therefore,

$N + F\sin\theta = mg\\ N = mg-F\sin\theta$

Frictional force is given as:

$f=\mu N=\mu (mg-F \sin \theta)=0.161\times ((15.7\times 9.8)-(83.1\times \sin(25.7))=18.97\textrm{ N}$

Now, friction acts in the direction opposite to the displacement. Thus, angle between frictional force and displacement is 180°.

Therefore, work done by friction is:

$W_{fric}=f\times d\times \cos\theta_f\\W_{fric}=12.72\times 62.6\times \cos(-180)\\W_{fric}=18.97\times 62.6\times -1\\W_{fric}=-1187.5\textrm{ J}$

Negative sign indicates that frictional force is acting opposite to motion.

So, the magnitude of the work done by the force of friction is 1187.5 J.

8 0

4 years ago

Which marine habitats would have the least access to primary producers?

nikitadnepr [17]

Answer:

D

Explanation:

4 0

2 years ago