To solve this problem you must apply the proccedure shown below:
1. You have the following expression given in the problem above:
![\sqrt[3]{216 x^{27} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B216%20x%5E%7B27%7D%20%7D%20)
2. Rewriting the expression we have:
![\sqrt[3]{6^3 x^{27} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B6%5E3%20x%5E%7B27%7D%20%7D%20)
3. You have that

and the exponent

are divisible by index

. Therefore, you have:
![\sqrt[3]{216 x^{27} } =6 x^{9}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B216%20x%5E%7B27%7D%20%7D%20%3D6%20x%5E%7B9%7D%20)
Therefore, as you can see,
the answer is the option, which is:
Answer:
The answer to your question is: ≈ 178 balls
Step-by-step explanation:
Data
rectangular prism = 8 in x 11 in x 5 in
golf balls = 1.68 in diameter
Formula
Volume rectangular prism = l x w x h = 8 x 11 x 5 = 440 in³
Volume of ball = (4/3) πr³ = (4/3) (3.1416) (0.84)³ = 2.48 in³
# of balls inside the compartment = volume rectangular prism / volume ball
# of balls = 440 / 2.48
= 177.4 ≈ 178 balls
The anwser is one and two tenths
Answer:
Yes
Step-by-step explanation:
It is a first-degree equation. Look at the exponents of each variable (x, y), they are not written because they are 1
Hope this helps
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