6N I think I’m pretty sure
<span>Assuming continuous operation (24/7), we can say that
Energy produced : Energy per hour * 24 (number of hours in a day) - 365 (number of days in a year.
Energy per hour: 2050 * 1.055 = 2162.75 kg.
So, we proceed to calculate the results
E: 2162.75 * 24 * 365 = 18,945,690 kj per year.
Now, we transform kj to megajoule, remembering that kilo is 10*3 and mega is 1'*6, so we divide the result by 1,000 in order to get the results in megajoules, and the answer would be:
18,945.69 megajoules can be produced per year.</span>
Explanation:
Let us assume that the maximum allowable horizontal distance be represented by "d".
Therefore, torque equation about A will be as follows.
d = ![\frac{[2 \times 75 \times (0.7+0.15+0.15) - 60 \times 0.15 - 252 \times 0.15 \times 2]}{252}](https://tex.z-dn.net/?f=%5Cfrac%7B%5B2%20%5Ctimes%2075%20%5Ctimes%20%280.7%2B0.15%2B0.15%29%20-%2060%20%5Ctimes%200.15%20-%20252%20%5Ctimes%200.15%20%5Ctimes%202%5D%7D%7B252%7D)
d = 0.409 m
Thus, we can conclude that the maximum allowable horizontal distance from the axle A of the wheelbarrow to the center of gravity of the second bag if she can hold only 75 N with each arm is 0.409 m.
Answer:
distance when the weight is 8 kg is 26.66 cm
Explanation:
given data
distance d2 = 10 cm
weight w2 = 3 kg
weight w1 = 8 kg
to find out
distance when the weight is 8 kg
solution
we consider here distance d1 when weight is 8 kg
so equation will be
d1/d2 = w1/w2
d/10 = 8/ 3
so d = 8/3 × 10
so d = 26.66
distance when the weight is 8 kg is 26.66 cm
Answer:
Explanation:
Let x ft be used to make square and 2-x ft be used to make equilateral triangle.
each side of square = x/4
area of square = ( x /4 )²
Each side of triangle
= (2-x) /3
Area of triangle = 1/2 (2-x)²/9 sin 60
= √3 / 36 x (2-x)²
Total area
A = ( x /4 )² +√3 / 36 (2-x)²
For maximum area
dA/dx = 0
1/16( 2x ) -√3 / 36 x2(2-x) = 0
x / 8 - √3(2-x)/ 18 = 0
x / 8 - √3/9 + √3/18 x = 0
x ( 1/8 + √3/18 ) = √3/9
x(.125 +.096 ) = .192
x = .868 ft
